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Chapter 1: Problem 55

Determine the temperature coefficient of a 5-V Zener diode (rated \(25^{\circ} \mathrm{C}\) value) if the nominal voltage drops to \(4.8 \mathrm{~V}\) at a temperature of \(100{ }^{\circ} \mathrm{C}\).

Short Answer

Expert verified
The temperature coefficient of the Zener diode is approximately \(0.001\degree C^{-1}\), which means the voltage drops by \(0.001V\) for every degree Celsius the temperature rises above the base temperature.

Step by step solution

01

Understand the variables

Firstly, identify the variables provided by the exercise. We have the nominal voltage \(V_{nom} = 5V\) at base temperature \(T_{base} = 25\degree C\), and the actual voltage \(V = 4.8V\) at elevated temperature \(T = 100\degree C\).
02

Check the formula for temperature coefficient

The formula for the temperature coefficient of a Zener diode is given by \(\alpha = (V_{nom} - V) / (V_{nom} \times (T - T_{base}))\).
03

Substitute values into the formula

Substituting the values from step 1 into the formula, we get \(\alpha = (5V - 4.8V) / (5V \times (100\degree C - 25\degree C))\). Now, proceed to calculate the value of \(\alpha\).

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