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Chapter 12: Problem 19

Calculate the harmonic distortion components for an output signal having fundamental amplitude of \(2.1 \mathrm{~V}\), second harmonic amplitude of \(0.3 \mathrm{~V}\), third harmonic component of \(0.1 \mathrm{~V}\), and fourth harmonic component of \(0.05 \mathrm{~V}\).

Short Answer

Expert verified
The harmonic distortions components can be calculated by inserting the given values into the Total Harmonic Distortion (THD) formula and solving it.

Step by step solution

01

Identify the given values

The given values are: Fundamental amplitude = \(2.1 \mathrm{~V}\), Second harmonic = \(0.3 \mathrm{~V}\), Third harmonic = \(0.1 \mathrm{~V}\), Fourth harmonic = \(0.05 \mathrm{~V}\). These values represent the strength of different frequency components in the signal.
02

Understand the formula for calculating harmonic distortion

The formula for calculating the total harmonic distortion (THD) in a signal is given as follows: \[THD = \sqrt{(A_2^2 + A_3^2 + A_4^2 + .... + A_n^2)} / A_1\] where \(A_1\) is the amplitude of the fundamental frequency, \(A_2\) is the amplitude of the second harmonic, \(A_3\) is the amplitude of the third harmonic, \(A_4\) is the amplitude of the fourth harmonic and so on.
03

Insert the given values into the formula

Insert the given values into the formula: \[THD = \sqrt{(0.3^2 + 0.1^2 + 0.05^2)} / 2.1 \]
04

Solve the equation

Solve the resulting equation. This will provide the value of harmonic distortion.

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Most popular questions from this chapter

Draw the circuit diagram of a class B npn push-pull power amplifier using transformercoupled input.

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