Chapter 13: Problem 16

Sketch the input and output waveforms for a one-shot using a 555 timer triggered by a \(10-\mathrm{kHz}\) clock for \(R_{A}=5.1 \mathrm{k} \Omega\) and \(C=5 \mathrm{nF}\).

Short Answer

Expert verified

The output waveform of the one-shot 555 timer consists of a series of pulses. Each pulse has a width of approximately 0.028ms and occurs every 0.1ms, corresponding to the 10kHz input triggering clock.

Step by step solution

Understand the Monostable mode of 555 Timer

The 555 timer in monostable mode is also known as a one-shot timer. When triggered by a pulse, it generates a fixed pulse and then awaits the next trigger.

Calculate the Output Waveform Period

The output waveform period (pulse width) of a monostable 555 timer can be calculated using the formula \(T = 1.1*R_{A}*C\). Let's plug in the given values: \(T = 1.1* 5.1k\Omega * 5nF\). When we calculate this, we find that \(T \approx 0.028 \mathrm{ms}\). This is the period of the output waveform.

Sketch the Input Waveform

The input waveform is given as a 10kHz clock. So, the input waveform would be a sequence of square pulses at a frequency of 10kHz. This means that each pulse is 0.1ms apart from each other.

Sketch the Output Waveform

The output waveform of a monostable 555 timer is a single pulse that begins when the input trigger pulse occurs and lasts for a duration of the pulse width we calculated earlier. This means that the output waveform would be a series of pulses, each with a width of 0.028ms and occurring every 0.1ms (to match the input waveform).

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Sketch the input and output waveforms for a one-shot using a 555 timer triggered by a \(10-\mathrm{kHz}\) clock for \(R_{A}=5.1 \mathrm{k} \Omega\) and \(C=5 \mathrm{nF}\).

Short Answer

Step by step solution

Understand the Monostable mode of 555 Timer

Calculate the Output Waveform Period

Sketch the Input Waveform

Sketch the Output Waveform

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