Calculate the rms ripple voltage at the output of an \(R C\) filter section that feeds a \(1-\mathrm{k} \Omega\) load when the filter input is \(50 \mathrm{~V}\) dc with \(2.5\) - \(\mathrm{V}\) rms ripple from a full-wave rectifier and capacitor filter. The \(R C\) filter section components are \(R=100 \Omega\) and \(C=100 \mu \mathrm{F}\).

Short Answer

Expert verified
The rms ripple voltage at the output of the RC filter section is computed to be approximately \(0.0066 V\) or \(6.6mV\), given the provided input parameters and using the rms ripple voltage output formula.

Step by step solution

01

Understanding the formula

Get acquainted with the formula for rms ripple voltage at the RC filter output: \(V_o=\frac{V_i}{(1+\sqrt{1+(2 \pi f R C)^2})}\) where \(V_o\) is the output rms ripple voltage, \(V_i\) is the input rms ripple voltage, R is the resistance in ohms, C is the capacitance in farads, and \(f\) is the frequency in hertz. For a full-wave rectifier, \(f = 120 Hz\). Given input rms ripple voltage = 2.5 V, R = 100 \(\Omega\), and C = 100 \(\mu F\), we can substitute these values into the formula to obtain \(V_o\).
02

Substitute the known values

Substitute the given values into the formula: \(V_o=\frac{2.5}{(1+\sqrt{1+(2 \pi 120 100 100 × 10^{-6})^2})}\).
03

Solve the equation

Solving the equation will yield the output ripple voltage. The computation is as follows: \(V_o=\frac{2.5}{(1+\sqrt{1+(753.9822)^2})}\). Solve for \(V_o\). This will provide the rms ripple voltage at the output of the RC filter section. It is important to execute the multiplication, square root, addition, and division operations in the correct order.

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