Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 15: Problem 9

A full-wave rectifier (operating from a 60-Hz supply) drives a capacitor- filter circuit \((C=100 \mu \mathrm{F})\), which develops \(12 \mathrm{~V}\) dc when connected to a \(2.5-\mathrm{k} \Omega\) load. Calculate the output voltage ripple.

Short Answer

Expert verified
By substituting the values into the formula, the value of the output voltage ripple can be calculated.

Step by step solution

01

Full-wave Rectifier Ripple Voltage Formula

First, remember the ripple voltage for a full wave rectifier with a capacitive filter can be calculated using the following formula: \(Vr = \frac {V} {fCR}\), where \(V\) is the peak voltage, \(f\) is the frequency, \(C\) is the capacitance and \(R\) is the resistance.
02

Convert Units

The unit of capacitance should be farads (F), frequency in hertz (Hz), resistance in ohms (Ω) and voltage in volts (V) to fit the formula. Given the load resistance \(R = 2.5 k \Omega\), this is equivalent to \(2.5 \times 10^3 \Omega\). The capacitance \(C = 100 \mu F\), is equivalent to \(100 \times 10^-6 F\). Now, these can be used as it is in the formula.
03

Find the peak voltage

The peak voltage of a full wave rectifier can be found by multiplying the dc voltage by the square root of 2. So, \(V = 12 \times \sqrt {2}\).
04

Plug into Formula

Substitute the values \(V, f, C\) and \(R\) into the ripple voltage formula \(\(Vr = \frac {V} {fCR}\)\) to find the output ripple voltage.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Calculate the size of the filter capacitor needed to obtain a filtered voltage having \(15 \%\) ripple at a load of \(150 \mathrm{~mA}\). The full-wave rectified voltage is \(24 \mathrm{~V}\) dc, and the supply is \(60 \mathrm{~Hz}\).

A full-wave rectified signal of \(18 \mathrm{~V}\) peak is fed into a capacitor filter. What is the voltage regulation of the filter if the output is \(17 \mathrm{~V} \mathrm{dc}\) at full load?

A \(500-\mu \mathrm{F}\) capacitor provides a load current of \(200 \mathrm{~mA}\) at \(8 \%\) ripple. Calculate the peak rectified voltage obtained from the 60 -Hz supply and the dc voltage across the filter capacitor.

Calculate the size of the filter capacitor needed to obtain a filtered voltage with \(7 \%\) ripple at a load of \(200 \mathrm{~mA}\). The full-wave rectified voltage is \(30 \mathrm{~V} \mathrm{dc}\) and the supply is \(60 \mathrm{~Hz}\).

A full-wave rectifier operating from the 60 -Hz ac supply produces a 20-V peak rectified voltage. If a \(200-\mu \mathrm{F}\) capacitor is used, calculate the ripple at a load of \(120 \mathrm{~mA}\).
See all solutions

Recommended explanations on Physics Textbooks

Waves Physics

Read Explanation

Conservation of Energy and Momentum

Read Explanation

Force

Read Explanation

Quantum Physics

Read Explanation

Magnetism

Read Explanation

Medical Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free