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Chapter 3: Problem 9

If the emitter current of a transistor is \(8 \mathrm{~mA}\) and \(I_{B}\) is \(1 / 100\) of \(I_{C}\), determine the levels of \(I_{C}\) and \(I_{B}\).

Short Answer

Expert verified
The levels of \(I_{C}\) and \(I_{B}\) are approximately \(7.92 \mathrm{~mA}\) and \(0.0792 \mathrm{~mA}\) respectively.

Step by step solution

01

Expression of \(I_{B}\) in terms of \(I_{C}\)

Given that base current \(I_{B}\) is \(1/100\) of the collector current \(I_{C}\), we can write this relation as \(I_{B}=I_{C}/100\).
02

Use the current conservation equation

We know, \(I_{E} = I_{B} + I_{C}\). Substituting \(I_{B}\) from step 1 into this equation, we get \(I_{E} = I_{C}/100 + I_{C}\).
03

Calculate the value of collector current \(I_{C}\)

Given the emitter current \(I_{E} = 8 \mathrm{~mA}\), substituting this value into the equation from step 2 and solving for \(I_{C}\), we find that \(I_{C}\) is approximately \(7.92 \mathrm{~mA}\).
04

Calculate the value of base current \(I_{B}\)

Using \(I_{B}=I_{C}/100\), and substituting the value from step 3 for \(I_{C}\), we find the base current \(I_{B}\) to be approximately \(0.0792 \mathrm{~mA}\).

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Most popular questions from this chapter

a. Given an \(\alpha_{\mathrm{dc}}\) of \(0.998\), determine \(I_{C}\) if \(I_{E}=4 \mathrm{~mA}\). b. Determine \(\alpha_{\mathrm{dc}}\) if \(I_{E}=2.8 \mathrm{~mA}\) and \(I_{B}=20 \mu \mathrm{A}\). c. Find \(I_{E}\) if \(I_{B}=40 \mu \mathrm{A}\) and \(\alpha_{\mathrm{dc}}\) is \(0.98\).

How must the two transistor junctions be biased for proper transistor amplifier operation?

From memory, sketch the transistor symbol for a \(p n p\) and an \(n p n\) transistor, and then insert the conventional flow direction for each current.

What is the source of the leakage current in a transistor?

From memory only, sketch the common-emitter configuration (for \(n p n\) and \(p n p\) ) and insert the proper biasing arrangement with the resulting current directions for \(I_{B}, I_{C}\), and \(I_{E}\).
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