Given a \(Q\) -point of \(I_{D_{Q}}=3 \mathrm{~mA}\) and \(V_{G S}=-3 \mathrm{~V}\), determine \(I_{D S S}\) if \(V_{P}=-6 \mathrm{~V}\).

Short Answer

Expert verified
The value of \(I_{D S S}\) is \(12 \mathrm{mA}\).

Step by step solution

01

Understand the given values and necessary formula

The known values from this question include: \(Q\)-point \(I_{D_{Q}}=3 \mathrm{~mA}\), \(V_{G S}=-3 \mathrm{~V}\), and \(V_{P}=-6 \mathrm{~V}\). We're tasked with finding \(I_{D S S}\). The applicable formula is \(-I_{D}\/I_{D S S}=(1-V_{G S}\/V_{P})^2\). Let's insert these known values into the formula.
02

Substitute the given values into the formula

Substitute the given values into the formula, we get: \(-3\/I_{D S S}=(1-(-3)\/-6)^2 = (1-0.5)^2 = 0.25\). Therefore, the equation can be written as \(-3\/I_{D S S}=0.25\).
03

Solve for \(I_{D S S}\)

To find \(I_{D S S}\), we need to isolate it on one side of the equation. We can multiply both sides with \(-1\) and then divide both sides by \(0.25\) to find \(I_{D S S}\). This gives us: \(I_{D S S}=3\/0.25 = 12 \mathrm{~mA}\).

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