If a JFET having a specified value of \(r_{d}=100 \mathrm{k} \Omega\) has an ideal voltage gain of \(A_{v}(\mathrm{FET})=-200\), what is the value of \(g_{m}\) ?

Short Answer

Expert verified
The value of \(g_{m}\) is \(-2 \mathrm{\mu S}\).

Step by step solution

01

Identify given parameters

The given parameters are \(r_{d} = 100 \mathrm{k} \Omega\) and \(A_{v}(\mathrm{FET}) = -200\).
02

Use the relation

The relation between the voltage gain, drain resistance and transconductance for a JFET is given by \(A_{v}(\mathrm{FET}) = g_{m} \cdot r_{d}\).
03

Solve for \(g_{m}\)

Substituting the given values to solve for \(g_{m}\), we get \[g_{m} = \frac{A_{v}(\mathrm{FET})}{r_{d}} = \frac{-200}{100 \mathrm{k} \Omega}\]

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