Chapter 13: Problem 5
Two-particle system. A \(2 \mathrm{~kg}\) particle is placed at \(x=2 \mathrm{~m}\) and a \(4 \mathrm{~kg}\) particle is placed at \(x=6 \mathrm{~m}\). (a) Where is the center of mass of this two-particle system?
Short Answer
Expert verified
The center of mass is at 4.67 m.
Step by step solution
01
Understand the formula for center of mass
The center of mass (COM) for a system of particles can be calculated using the formula: \[ x_{cm} = \frac{m_1 x_1 + m_2 x_2}{m_1 + m_2} \]where \( m_1 \) and \( m_2 \) are the masses of the particles, and \( x_1 \) and \( x_2 \) are their respective positions.
02
Substitute the given values
Given: - \( m_1 = 2 \, \text{kg} \)- \( x_1 = 2 \, \text{m} \)- \( m_2 = 4 \, \text{kg} \)- \( x_2 = 6 \, \text{m} \)Substitute these values into the COM formula:\[ x_{cm} = \frac{(2 \, \text{kg}) (2 \, \text{m}) + (4 \, \text{kg}) (6 \, \text{m})}{2 \, \text{kg} + 4 \, \text{kg}} \]
03
Perform the multiplication
Calculate the products:\[ (2 \, \text{kg})(2 \, \text{m}) = 4 \, \text{kg} \cdot \text{m} \]\[ (4 \, \text{kg})(6 \, \text{m}) = 24 \, \text{kg} \cdot \text{m} \]
04
Add the products
Sum the products found in Step 3:\[ 4 \, \text{kg} \cdot \text{m} + 24 \, \text{kg} \cdot \text{m} = 28 \, \text{kg} \cdot \text{m} \]
05
Divide by the total mass
Total mass = \( 2 \, \text{kg} + 4 \, \text{kg} = 6 \, \text{kg} \)Divide the total product by the total mass:\[ x_{cm} = \frac{28 \, \text{kg} \cdot \text{m}}{6 \, \text{kg}} = 4.67 \, \text{m} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
center of mass
The center of mass (COM) is a fundamental concept in physics and mechanics. It refers to a point in a system of particles where the whole mass of the system can be considered to be concentrated. For a system composed of different masses at varying positions, the center of mass can be calculated using a weighted average of their positions. This simplifies the study of motion because it allows us to analyze the motion of one single point instead of multiple points. Essentially, the motion of the entire system can be described by the motion of the center of mass. The formula used for finding the x-coordinate of the center of mass in a two-particle system is:
\[ x_{cm} = \frac{m_1 x_1 + m_2 x_2}{m_1 + m_2} \]
Here, \( m_1 \) and \( m_2 \) are the masses of the particles, and \( x_1 \) and \( x_2 \) are their respective positions. By substituting the given values, you can find the exact position of the center of mass along the x-axis.
\[ x_{cm} = \frac{m_1 x_1 + m_2 x_2}{m_1 + m_2} \]
Here, \( m_1 \) and \( m_2 \) are the masses of the particles, and \( x_1 \) and \( x_2 \) are their respective positions. By substituting the given values, you can find the exact position of the center of mass along the x-axis.
two-particle system
A two-particle system is one of the simplest systems used to understand the principles of mechanics and the concept of the center of mass. In this exercise, we're focusing on a system with two particles of different masses placed at specific positions along a line. Given:
By substituting the values in the formula:
\[ x_{cm} = \frac{(2 \text{ kg})(2 \text{ m}) + (4 \text{ kg})(6 \text{ m})}{2 \text{ kg} + 4 \text{ kg}} = 4.67 \text{ m} \]you find that the center of mass of this system is at 4.67 meters from the origin. This calculated point is the effective position where the combined mass behaves as if it were concentrated at that single point.
- A 2 kg particle at 2 meters
- A 4 kg particle at 6 meters
By substituting the values in the formula:
\[ x_{cm} = \frac{(2 \text{ kg})(2 \text{ m}) + (4 \text{ kg})(6 \text{ m})}{2 \text{ kg} + 4 \text{ kg}} = 4.67 \text{ m} \]you find that the center of mass of this system is at 4.67 meters from the origin. This calculated point is the effective position where the combined mass behaves as if it were concentrated at that single point.
mechanics
Mechanics is a branch of physics that deals with the motion of objects and the forces acting on them. One fundamental concept within mechanics is the center of mass. Understanding how to calculate the center of mass allows us to predict and describe the motion of objects more accurately. In the context of this exercise, mechanics principles are applied to a two-particle system.
Key points to grasp include:
Key points to grasp include:
- The center of mass depends on both the masses of the particles and their positions.
- By treating multiple particles as a single point at the center of mass, complex motion becomes simpler to analyze.
- The center of mass is crucial in mechanics as it simplifies the equations of motion and is used in various applications from simple physics problems to sophisticated engineering designs.