Pulling a train. A locomotive exerts a force \(F=20,000 \mathrm{~N}\) on a train cart loaded with automobiles. The mass of the cart, including its load, is \(10,000 \mathrm{~kg}\). (a) What is the acceleration of the train cart? Another car with mass \(2000 \mathrm{~kg}\) is added to the load on the train cart. (b) What is the acceleration of the train cart now?

Short Answer

Expert verified
For part (a), the acceleration is 2 \(\mathrm{m/s^2}\). For part (b), the acceleration is 1.67 \(\mathrm{m/s^2}\).

Step by step solution

01

- Identify the given values for part (a)

The force exerted by the locomotive, \( F \), is 20,000 N. The mass of the cart, \( m \), is 10,000 kg.
02

- Apply Newton's Second Law for part (a)

Newton's Second Law states that \( F = ma \). Rearrange this equation to solve for acceleration: \( a = \frac{F}{m} \).
03

- Calculate acceleration for part (a)

Substitute the given values into the equation: \( a = \frac{20,000 \mathrm{~N}}{10,000 \mathrm{~kg}} = 2 \mathrm{~m/s^2} \).
04

- Identify the new mass for part (b)

The original mass of the cart is 10,000 kg. An additional car with mass 2,000 kg is added. Therefore, the total mass now is \( 10,000 \mathrm{~kg} + 2,000 \mathrm{~kg} = 12,000 \mathrm{~kg} \).
05

- Apply Newton's Second Law for part (b)

Using the same formula, \( a = \frac{F}{m} \), with the updated mass.
06

- Calculate acceleration for part (b)

Substitute the new values into the equation: \( a = \frac{20,000 \mathrm{~N}}{12,000 \mathrm{~kg}} = 1.67 \mathrm{~m/s^2} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

force and acceleration
Newton's Second Law is key to understanding how force and acceleration work together. It tells us that the force applied to an object is equal to the mass of the object times its acceleration. This can be summarized by the formula:
  • \[ F = ma \]
In simpler terms, if you push on something, how much it will speed up depends on how hard you push and how heavy it is. More force means more acceleration, and a heavier mass means less acceleration for the same amount of force.
In our exercise, the locomotive exerts a force of 20,000 N on the train cart. The mass of the cart is 10,000 kg. Using the formula, we can solve for acceleration:
  • \[ a = \frac{F}{m} = \frac{20,000 \text{~N}}{10,000 \text{~kg}} = 2 \text{~m/s}^2 \]
So, the train cart accelerates at 2 m/s^2.
Now, if an additional car with mass 2,000 kg is added, the total mass becomes 12,000 kg. We use the same formula to find the new acceleration:
  • \[ a = \frac{20,000 \text{~N}}{12,000 \text{~kg}} = 1.67 \text{~m/s}^2 \]
The acceleration decreases because the mass has increased, but the force remains the same.
mass and weight
Mass and weight are closely related but are not the same thing. Mass refers to the amount of matter in an object and is measured in kilograms (kg). It stays the same no matter where you are. For example, a bag of rice will always have the same mass whether you're on Earth or the Moon.
Weight, on the other hand, is the force exerted by gravity on that mass. It depends on both the mass and the gravitational pull of the place you are in. Weight is calculated by the formula:
  • \[ \text{Weight} = \text{mass} \times g \]
where \[ g \] is the acceleration due to gravity (approximately 9.81 \[ \text{m/s}^2 \] on Earth).
For example, if our train cart were on Earth, its weight would be:
  • \[ \text{Weight} = 10,000 \text{~kg} \times 9.81 \text{~m/s}^2 = 98,100 \text{~N} \]
Adding another 2,000 kg car to the load would increase the weight:
  • \[ \text{Weight} = 12,000 \text{~kg} \times 9.81 \text{~m/s}^2 = 117,720 \text{~N} \]
So, mass is the same, but weight changes based on the gravitational pull of your location.
mechanical physics
Mechanical physics deals with the behavior of physical bodies when subjected to forces or displacements. In the context of our exercise, it helps explain how the train cart moves when a force is applied.
Key concepts in mechanical physics include:
  • Force: A push or pull on an object.
  • Acceleration: The rate at which an object's velocity changes over time.
  • Mass: The amount of matter in an object.
Newton's Second Law, which we've been using, is fundamental in this field. It states that the force exerted on an object is the product of its mass and acceleration:
  • \[ F = ma \]
Beyond our example, mechanical physics covers many other areas like:
  • Momentum: The quantity of motion an object has, dependent on its mass and velocity.
  • Energy: The capacity to do work, present in various forms such as kinetic and potential energy.
  • Work: The transfer of energy when an object is moved over a distance by an external force.
In our exercise, understanding the relationship between force, mass, and acceleration is crucial for predicting how the train cart will move when an additional load is added.

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Most popular questions from this chapter

Space shuttle with air resistance. During lift-off of the space shuttle the engines provide a force of 35 million Newtons. The mass of the shuttle is approximately 2 million \(\mathrm{kg}\). (a) Draw a free-body diagram of the space shuttle immediately after lift-off. (b) Find an expression for the acceleration of the space shuttle immediately after lift-off. Let us assume that the force from the engines is constant, and that the mass of the space shuttle does not change significantly over the first \(20 \mathrm{~s}\). (c) Find the velocity and position of the space shuttle after \(20 \mathrm{~s}\) if you ignore air resistance. Let us assume that we can describe the air resistance force on the space shuttle with a square law, \(F=-D v|v|\), where \(D \simeq 388 \mathrm{~kg} / \mathrm{m} .\) (d) Develop a program to find the velocity and position of the space shuttle using numerical methods. (e) Find the velocity and position of the space shuttle after \(20 \mathrm{~s}\) if you include air resistance. (f) Plot the velocity and position and compare with the results without air resistance. Comment on the results. Notice that \(D\) depends on the density of the surrounding air, and the density falls when as the shuttle ascends, hence \(D\) actually depends on the height of the shuttle.

Stretching an aluminum wire. A thin aluminum wire is stretched \(1 \mathrm{~mm}\) when a \(10 \mathrm{~kg}\) weight is suspended from it. Assume the wire can be modelled as a spring, what is the spring constant for the wire?

Two masses and a spring. Two particles of \(m=0.1 \mathrm{~kg}\) are attached with a spring with spring constant \(k=100 \mathrm{~N} / \mathrm{m}\) and equilibrium length \(b=0.01 \mathrm{~m}\). Both particles start at rest and the spring is at equilibrium. An external force \(F=1000 \mathrm{~N}\) acts during \(1 \mathrm{~s}\) on one of the particles in the direction of the other particle. Find the position of both particles as a function of time from the time \(t=0 \mathrm{~s}\) when the external force starts acting. (You may solve this problem analytically or numerically).

Experiments in Pisa. On a visit to Pisa, you decide to redo Galileo's original experiment based on your knowledge of physics. You bring to steel spheres of the same size to the top of the tower. One sphere is hollow and the other is solid. (a) Draw a free-body diagram for one of the spheres. (b) How would you describe air resistance for each of the spheres? (c) Find an expression for the acceleration of the sphere as a function of its mass. (d) Which of the two spheres have the largest acceleration?

In the army. You are told by a friend in the army that the force you feel when you fire a gun is the same as the force felt by a sandbag hit by the bullet because the two forces are action-reactions pairs. Is this true?

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