A small monkey is climbing far out on a branch when it suddenly breaks. The branch does not snap off, but start to rotate about the point where it is broken. The monkey clings to the branch. What is the direction of the acceleration of the monkey?

Short Answer

Expert verified
The acceleration of the monkey is directed towards the point where the branch is broken.

Step by step solution

01

- Identify the Rotation Center

Determine the point about which the branch rotates. The branch rotates about the point where it is broken.
02

- Understand Circular Motion

When the branch rotates, the monkey undergoes circular motion around the rotation center. In circular motion, the direction of acceleration is always towards the center of the circle (centripetal acceleration).
03

- Determine the Acceleration Direction

Since the monkey is clinging to the branch and undergoing circular motion, the acceleration is directed towards the center of the circular path, which is the rotation point of the branch.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centripetal Acceleration
When an object moves in a circular path, it experiences an inward acceleration called centripetal acceleration. This acceleration is always directed towards the center of the circle. The word 'centripetal' itself means 'center-seeking'. This is crucial for maintaining the circular motion.

Imagine swinging a ball on a string in a circle. The tension in the string provides the centripetal force, pulling the ball towards the center. Similarly, for the monkey clinging to the rotating branch, centripetal acceleration pulls the monkey towards the branch's rotation center. This ensures the monkey follows a circular trajectory instead of flying off in a straight line.

We can mathematically express centripetal acceleration using the formula:

\[a_c = \frac{v^2}{r}\]

Where:
  • a_c is the centripetal acceleration
  • v is the velocity of the object in motion

  • r is the radius of the circular path

This formula shows that centripetal acceleration increases with the square of the velocity and decreases as the radius of the circle grows.
Rotation Center
The rotation center, also known as the pivot or axis of rotation, is the fixed point around which a body rotates. For the monkey and the broken branch, the rotation center is the point where the branch is broken and remains connected to the tree. Everything on the branch, including the monkey, moves around this point, causing circular motion.

Imagine the rotation center as the heart of the circular pathway. It's where all the rotational activity originates. For the broken branch scenario, the part still attached to the tree acts as the fulcrum or pivot point. The rest of the branch moves around this center, creating a circular path for the monkey.

Understanding the role of the rotation center helps visualize why the monkey's acceleration points inward towards this pivot. No matter where the monkey is positioned on the branch, its acceleration will always be directed towards this fixed point.
Circular Motion
Circular motion refers to the movement of an object along the circumference of a circle. This type of motion is characterized by a constant distance from a central point, known as the center of rotation.

When the monkey clings to the broken branch, it undergoes circular motion around the rotation center. This means that despite the branch moving, the monkey's distance from the break point (the rotation center) remains constant. The key to understanding circular motion lies in the forces at play.

In circular motion, an inward force pulls the object towards the rotation center. This inward pull causes the centripetal acceleration discussed earlier. Without this force, objects would not travel in a circular path and would instead move in a straight line due to inertia.

To sum up:
  • Circular motion requires a constant inward force for maintaining the trajectory.
  • This inward pull results in centripetal acceleration.
  • Examples of circular motion include planets orbiting around the sun, cars taking a turn, and indeed, a monkey clinging to a rotating branch.

Understanding these concepts makes it easier to visualize why the monkey's acceleration on the rotating branch points towards the rotation center, ensuring it continues its circular journey.

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Most popular questions from this chapter

Your spaceship has been designed with a large rotating wheel to give an impression of gravity. The radius of the wheel is \(R=50 \mathrm{~m}\). (a) How many rotation per minutes must the wheel execute for the acceleration at the outer end of the wheel to correspond to the acceleration of gravity at the Earth, \(g=9.8 \mathrm{~m} / \mathrm{s}^{2}\) ? (b) What is the difference in acceleration of your feet and your head if you are standing with your feet at the outer end of the rotating wheel? You can assume that you are approximately \(2 \mathrm{~m}\) high.

Your spaceship has been designed with a large rotating wheel to give an impression of gravity. The radius of the wheel is \(R=50 \mathrm{~m}\). (a) How many rotation per minutes must the wheel execute for the acceleration at the outer end of the wheel to correspond to the acceleration of gravity at the Earth, \(g=9.8 \mathrm{~m} / \mathrm{s}^{2}\) ? (b) What is the difference in acceleration of your feet and your head if you are standing with your feet at the outer end of the rotating wheel? You can assume that you are approximately \(2 \mathrm{~m}\) high.

During a \(200 \mathrm{~m}\) race, a sprinter is running with a speed of \(10 \mathrm{~m} / \mathrm{s}\) through the first curve. The length of the curve is \(100 \mathrm{~m}\). (a) Find the radius, \(R\), of the curve (it is a perfect half-circle). (b) Find the magnitude and direction of the acceleration \(a\) of the sprinter.

Trning a high-speed train. A high speed train holds a constant speed of \(200 \mathrm{~km} / \mathrm{h}\). Your job is to design a \(90^{\circ}\) turn. Let us assume that you design the turn as a part of a circle. (a) Find an expression for the acceleration of the train while turning. (b) How large must the radius of the circle be for the acceleration to be smaller than \(0.1 \mathrm{~g}\), where \(g=9.8 \mathrm{~m} / \mathrm{s}^{2} ?\) (c) How long time does the turn take?

A skier is pulled up a hill with an inclination \(\alpha\) with the horizontal. He is pulled with a constant acceleration of \(a=2 \mathrm{~m} / \mathrm{s}^{2}\) along the hill and starts from rest at the bottom of the hill. (a) Find the speed, \(v(t)\), of the skier measured along the slope as a function of time, \(t\). (b) Find the position, \(s(t)\), of the skier measured as a distance from the starting point after a time \(t\). (c) Find the position, \(\mathbf{r}(t)\), of the skier in the \(x y\)-coordinate system, where \(x\) is the horizontal axis and \(y\) is the vertical axis. (d) Use the vector position, \(\mathbf{r}(t)\), to find the speed of the skier, and compare with the results you found above.

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