As a stunt motorcyclist you are trying to run through a vertical loop with radius \(3 \mathrm{~m}\). What speed do you need to have at the top of the loop in order not to fall down?

Short Answer

Expert verified
About 5.42 m/s

Step by step solution

01

Understand the forces acting at the top of the loop

At the top of the loop, the only force acting on the motorcycle is gravity (weight), which must provide the necessary centripetal force to keep the motorcycle moving in a circular path.
02

Apply the condition for minimum speed

The condition for the minimum speed at the top of the loop is that the gravitational force (mg) must be equal to the centripetal force needed to keep the motorcycle in circular motion, which can be expressed as: \[ mg = \frac{mv^2}{r} \]
03

Solve for speed

Given that the radii of the loop (r) is 3 meters and the gravitational acceleration (g) is approximately 9.8 m/s², substitute these values into the equation: \[ mg = \frac{mv^2}{3} \]By simplifying, we get: \[ g = \frac{v^2}{3} \]Solving for v gives: \[ v^2 = 3g \]Finally, take the square root to find the speed: \[ v = \frac{\text{0} + \text{SqaureRoot}} \]\[ v = \sqrt{3 \times 9.8} \] \[ v \approx 5.42 \text{ m/s} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Force
Gravitational force is one of the fundamental forces of nature. It is the force that pulls objects toward the center of the Earth and keeps us grounded. This force is described by the equation \( F = mg \), where \( F \) is the force, \( m \) is the mass of the object, and \( g \) is the acceleration due to gravity, approximately \( 9.8 \text{ m/s}^2 \).
Minimum Speed
When discussing the minimum speed required to stay in a curved path, we refer to the point where gravitational force alone provides the required centripetal force.
Circular Motion
Circular motion refers to an object moving along the boundary of a circle. This type of motion is influenced by a centripetal force, which is always directed towards the center of the circle.

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Most popular questions from this chapter

Walking on ice is usually more tiring than walking on a dry road. Why?

In this project we will study a phenomenon called stickslip friction. If you pull a block along a flat table with a soft spring, you will find that the block does not move continuously with a constant velocity, instead it moves in small jumps. This intermittent motion is called stick-slip friction, and it is the origin of the high-frequency vibrating tone you often hear from wheels that are not well lubricated. It is also one of the basic mechanisms leading to the wide distribution of earthquake sizes. Here, we will introduce and study a model for stick-slip friction for a block pulled by a spring sliding over a flat, horizontal surface, as illustrated in Fig. \(9.18\). The block has mass \(m\). A massless spring (with spring constant \(k\) and equilibrium length \(b\) ) is attached to the block at the point \(x\). The free end (the right-hand end in Fig. 9.18) of the spring is at the point \(x_{b}\). We move \(x_{b}\), the free end of the spring, with a constant velocity \(u\). 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