A standing wave ratio of \(2.5\) exists on a lossless \(60 \Omega\) line. Probe measurements locate a voltage minimum on the line whose location is marked by a small scratch on the line. When the load is replaced by a short circuit, the minima are \(25 \mathrm{~cm}\) apart, and one minimum is located at a point \(7 \mathrm{~cm}\) toward the source from the scratch. Find \(Z_{L}\).

Short Answer

Expert verified
Answer: The load impedance (\(Z_L\)) is 150 ohms.

Step by step solution

01

Calculate the reflection coefficient

Using the given SWR value, we can calculate the reflection coefficient (\(\Gamma\)) using the following formula: $$\Gamma = \frac{SWR - 1}{SWR + 1}$$ Plug in the given SWR value of 2.5: $$\Gamma = \frac{2.5 - 1}{2.5 + 1} = \frac{1.5}{3.5} = 0.4286$$
02

Find the normalized load impedance

Next, we will use the reflection coefficient to find the normalized load impedance (\(z_L\)) as follows: $$z_L = \frac{1 + \Gamma}{1 - \Gamma}$$ Plugging in the value of \(\Gamma\) obtained in step 1: $$z_L = \frac{1 + 0.4286}{1 - 0.4286} = \frac{1.4286}{0.5714} = 2.5$$
03

Calculate the angle θ of the complex reflection coefficient

We're given the information that the minima are 25 cm apart, and there is a minimum located at a point 7 cm towards the source from the scratch. Therefore, the scratch is located between two adjacent minima. The total electrical length between two adjacent minima (from minimum to maximum to another minimum) is \(\pi\). We can calculate the angle θ as follows: $$\theta = \pi \frac{7}{25}$$
04

Convert the normalized load impedance to the actual load impedance

Now, we will convert the normalized load impedance (\(z_L\)) to the actual load impedance (\(Z_L\)) using the following formula: $$Z_L = z_L * Z_0$$ Where \(Z_0\) is the characteristic impedance of the line, which is 60 ohms. Plugging in the values: $$Z_L = 2.5 * 60 = 150 \Omega$$ Therefore, the load impedance (\(Z_L\)) is equal to 150 ohms.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reflection Coefficient
In the context of transmission lines, the reflection coefficient, represented as \( \Gamma \), is a measure of how much of an electromagnetic wave is reflected by an impedance discontinuity in the transmission line. The reflection can occur at the interface between the line and the load when there's a mismatch between the load impedance and the characteristic impedance of the line.

The reflection coefficient is calculated using the formula: \[\Gamma = \frac{SWR - 1}{SWR + 1}\] where SWR stands for the Standing Wave Ratio. A reflection coefficient of 1 indicates total reflection (open or short circuit) and a coefficient of 0 indicates no reflection, which means the load is perfectly matched.

In our exercise, an SWR of 2.5 leads to a reflection coefficient of 0.4286, indicating there's a significant mismatch between the load and the characteristic impedance, causing a substantial amount of the wave to be reflected back.
Normalized Load Impedance
Normalized load impedance (\(z_L\)) is a dimensionless quantity that represents the load impedance relative to the characteristic impedance of the line \(Z_0\). It is used to simplify the analysis of transmission lines by scaling impedances so that the characteristic impedance is unity.

To find the normalized load impedance, we use the reflection coefficient obtained from the SWR with the formula: \[z_L = \frac{1 + \Gamma}{1 - \Gamma}\]. This formula calculates how much the actual load impedance (\(Z_L\)) deviates from the characteristic impedance.

When we plug our \( \Gamma \) into this formula, we get a normalized load impedance of 2.5, implying that the load impedance is 2.5 times greater than the characteristic impedance of the line.
Characteristic Impedance
Characteristic impedance (\(Z_0\)) of a transmission line is a key parameter that dictates how electrical signals are conducted by the line. It is a measure of the inherent resistance to the flow of electrical current and is determined by the physical construction of the line, including the dimensions and materials used. \(Z_0\) provides a balance between electric and magnetic fields propagating the wave along the line.

In our problem, the line has a characteristic impedance of 60 ohms. With the normalized load impedance of 2.5 and the actual load impedance formula (\(Z_L = z_L * Z_0\)), the true load impedance comes out to be 150 ohms. This indicates that the load is higher than what the line 'expects', leading to inefficiencies such as reflections and non-optimal power transfer, which are depicted by the standing wave pattern measured on the line.

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Most popular questions from this chapter

A \(300-\Omega\) transmission line is short-circuited at \(z=0\). A voltage maximum, \(|V|_{\max }=10 \mathrm{~V}\), is found at \(z=-25 \mathrm{~cm}\), and the minimum voltage, \(|V|_{\min }=\) 0 , is at \(z=-50 \mathrm{~cm}\). Use the Smith chart to find \(Z_{L}\) (with the short circuit replaced by the load) if the voltage readings are \((a)|V|_{\max }=12 \mathrm{~V}\) at \(z=\) \(-5 \mathrm{~cm}\), and \(|V|_{\min }=5 \mathrm{~V} ;(b)|V|_{\max }=17 \mathrm{~V}\) at \(z=-20 \mathrm{~cm}\), and \(|V|_{\min }=0 .\)

A sinusoidal voltage source drives the series combination of an impedance, \(Z_{g}=50-j 50 \Omega\), and a lossless transmission line of length \(L\), shorted at the load end. The line characteristic impedance is \(50 \Omega\), and wavelength \(\lambda\) is measured on the line. \((a)\) Determine, in terms of wavelength, the shortest line length that will result in the voltage source driving a total impedance of \(50 \Omega .(b)\) Will other line lengths meet the requirements of part \((a)\) ? If so, what are they?

The characteristic admittance \(\left(Y_{0}=1 / Z_{0}\right)\) of a lossless transmission line is \(20 \mathrm{mS}\). The line is terminated in a load \(Y_{L}=40-j 20 \mathrm{mS}\). Use the Smith chart to find \((a) s ;(b) Y_{\text {in }}\) if \(l=0.15 \lambda ;(c)\) the distance in wavelengths from \(Y_{I}\) to the nearest voltage maximum.

In a circuit in which a sinusoidal voltage source drives its internal impedance in series with a load impedance, it is known that maximum power transfer to the load occurs when the source and load impedances form a complex conjugate pair. Suppose the source (with its internal impedance) now drives a complex load of impedance \(Z_{L}=R_{L}+j X_{L}\) that has been moved to the end of a lossless transmission line of length \(\ell\) having characteristic impedance \(Z_{0}\). If the source impedance is \(Z_{g}=R_{g}+j X_{g}\), write an equation that can be solved for the required line length, \(\ell\), such that the displaced load will receive the maximum power.

The parameters of a certain transmission line operating at \(\omega=6 \times 10^{8} \mathrm{rad} / \mathrm{s}\) are \(L=0.35 \mu \mathrm{H} / \mathrm{m}, C=40 \mathrm{pF} / \mathrm{m}, G=75 \mu \mathrm{S} / \mathrm{m}\), and \(R=17 \Omega / \mathrm{m}\). Find \(\gamma, \alpha, \beta, \lambda\), and \(Z_{0}\)

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