(a) Most microwave ovens operate at \(2.45 \mathrm{GHz}\). Assume that \(\sigma=1.2 \times\) \(10^{6} \mathrm{~S} / \mathrm{m}\) and \(\mu_{r}=500\) for the stainless steel interior, and find the depth of penetration. \((b)\) Let \(E_{s}=50 \angle 0^{\circ} \mathrm{V} / \mathrm{m}\) at the surface of the conductor, and plot a curve of the amplitude of \(E_{s}\) versus the angle of \(E_{s}\) as the field propagates into the stainless steel.

Short Answer

Expert verified
Answer: The depth of penetration of the microwave ovens in the stainless steel interior is approximately \(2.298 \times 10^{-6} \, \text{m}\). To plot the curve of the amplitude of the electric field versus the angle, we can use the equation \(E(x) = 50 e^{(-x/2.298 \times 10^{-6})} \angle{(1.54 \times 10^{10} x / 2.298 \times 10^{-6})}\) and any plotting software.

Step by step solution

01

Find the angular frequency

To start, we need to find the angular frequency (\(\omega\)) of the microwave ovens. We are given the operating frequency (\(f\)) as \(2.45 \times 10^9 \, \text{Hz}\). The angular frequency can be found using the following formula: \(\omega = 2\pi f\) Plugging in the values, we find the \(\omega\): \(\omega = 2\pi (2.45 \times 10^9) = 1.54 \times 10^{10} \, \text{rad/s}\)
02

Find the skin depth

We'll now use the given values of conductivity (\(\sigma\)) and relative permeability (\(\mu_r\)) to find the depth of penetration (or skin depth) using the following formula: $ \delta = \sqrt{\frac{2}{\omega\mu\sigma}} $ We must first calculate the permeability (\(\mu\)) as follows: $ \mu = \mu_r \mu_0, $ where \(\mu_0 = 4\pi \times 10^{-7} \, \text{T} \cdot \text{m} / \text{A}\) is the permeability of free space. $ \mu = 500 \cdot (4\pi \times 10^{-7}) = 6.283 \times 10^{-4} \, \text{T} \cdot \text{m} / \text{A} $ Now, we can use the \(\mu\) value to find the skin depth (\(\delta\)): $ \delta = \sqrt{\frac{2}{(1.54 \times 10^{10})(6.283 \times 10^{-4})(1.2 \times 10^6)}} = 2.298 \times 10^{-6} \, \text{m} $ So, the depth of penetration is approximately \(2.298 \times 10^{-6} \, \text{m}\).
03

Find the amplitude and angle equations of the electric field

We are given the amplitude of the electric field at the surface as \(E_s = 50 \angle 0^{\circ} \, \text{V} / \text{m}\). The electric field (\(E\)) at any depth (\(x\)) can be found using the following equation: $ E(x) = E_s e^{-x/\delta} \angle{(\omega x/\delta)} $ By substituting the given values of \(E_s\) and the calculated values of \(\delta\) and \(\omega\), we can find the electric field at any depth: $ E(x) = 50 e^{(-x/2.298 \times 10^{-6})} \angle{(1.54 \times 10^{10} x / 2.298 \times 10^{-6})} $
04

Plot the curve

Using any plotting software, we can now plot the curve of the amplitude of the electric field versus the angle of the electric field as the field propagates into the stainless steel interior using the equation obtained in the previous step. To summarize, we found the depth of penetration of the microwave ovens in the stainless steel interior to be approximately \(2.298 \times 10^{-6} \, \text{m}\). Then, by using the given amplitude of the electric field at the surface and the equations, we obtained an equation for the electric field at any depth. Using this equation, we can plot the curve of the amplitude of the electric field versus the angle.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Microwave Ovens Frequency
Microwave ovens operate on a specific frequency to heat food efficiently. Most microwave ovens use a frequency of 2.45 gigahertz (GHz), which translates to a wavelength that water molecules, present in most foods, can absorb effectively. This absorption excites the water molecules, creating heat through friction, ultimately cooking the food.

When engineers design microwave ovens, they must consider how the frequency interacts with the interior materials of the oven, like the stainless steel walls. The operating frequency not only determines how the food is heated, but also how deeply the microwaves penetrate into the oven's internal surfaces. Precise calculations are important to ensure safety and efficiency, as well as to avoid interference with other electronic devices operating on nearby frequencies.
Electromagnetic Field Penetration
The depth of penetration, often referred to as skin depth, is a measure of how far an electromagnetic field can penetrate into a conductor before it decays significantly. This concept is pivotal in understanding how microwave ovens work and how the microwaves interact with the materials inside them.

The skin depth is influenced by the frequency of the electromagnetic field, the electrical conductivity, and the magnetic permeability of the material. Calculating the skin depth involves these variables, and the depth can be very shallow for high frequencies or for materials with high electrical conductivity and magnetic permeability. This is particularly relevant in microwave ovens, where the penetration depth determines how the microwaves interact with the oven's stainless steel interior, affecting design considerations to ensure the safe containment of microwaves within the oven.
Electric Field Amplitude
The electric field amplitude is a quantitative expression of the magnitude of the electric field at a given point in space. For a microwave oven, the electric field amplitude at the surface of the stainless steel interior is an important parameter. It determines the initial intensity of the microwaves as they begin to penetrate the material of the oven's walls.

The amplitude of the electric field decreases exponentially with distance from the surface due to the conductive nature of the metal, following the skin depth principle. This measurement is essential for plotting the expected behavior of the field as it moves through the material, and ultimately for ensuring that the design of the oven directs the microwaves appropriately to heat food without causing damage to the oven itself or to its surroundings.

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Most popular questions from this chapter

Consider a left circularly polarized wave in free space that propagates in the forward \(z\) direction. The electric field is given by the appropriate form of Eq. (100). Determine ( \(a\) ) the magnetic field phasor, \(\mathbf{H}_{s} ;(b)\) an expression for the average power density in the wave in \(\mathrm{W} / \mathrm{m}^{2}\) by direct application of Eq. (77).

The planar surface \(z=0\) is a brass-Teflon interface. Use data available in Appendix \(\mathrm{C}\) to evaluate the following ratios for a uniform plane wave having \(\omega=4 \times 10^{10} \mathrm{rad} / \mathrm{s}:\left(\right.\) a) \(\alpha_{\text {Tef }} / \alpha_{\text {brass }} ;(b) \lambda_{\text {Tef }} / \lambda_{\text {brass }} ;\) (c) \(v_{\text {Tef }} / v_{\text {brass }}\).

A linearly polarized uniform plane wave, propagating in the forward \(z\) direction, is input to a lossless anisotropic material, in which the dielectric constant encountered by waves polarized along \(y\left(\epsilon_{r y}\right)\) differs from that seen by waves polarized along \(x\left(\epsilon_{r x}\right) .\)

Voltage breakdown in air at standard temperature and pressure occurs at an electric field strength of approximately \(3 \times 10^{6} \mathrm{~V} / \mathrm{m}\). This becomes an issue in some high-power optical experiments, in which tight focusing of light may be necessary. Estimate the lightwave power in watts that can be focused into a cylindrical beam of \(10 \mu \mathrm{m}\) radius before breakdown occurs. Assume uniform plane wave behavior (although this assumption will produce an answer that is higher than the actual number by as much as a factor of 2 , depending on the actual beam shape).

Given a \(100-\mathrm{MHz}\) uniform plane wave in a medium known to be a good dielectric, the phasor electric field is \(\mathcal{E}_{s}=4 e^{-0.5 z} e^{-j 20 z} \mathbf{a}_{x} \mathrm{~V} / \mathrm{m}\). Determine (a) \(\epsilon^{\prime} ;(b) \epsilon^{\prime \prime} ;(c) \eta ;(d) \mathbf{H}_{s} ;(e)\langle\mathbf{S}\rangle ;(f)\) the power in watts that is incident on a rectangular surface measuring \(20 \mathrm{~m} \times 30 \mathrm{~m}\) at \(z=10 \mathrm{~m}\).

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