The planar surface \(z=0\) is a brass-Teflon interface. Use data available in Appendix \(\mathrm{C}\) to evaluate the following ratios for a uniform plane wave having \(\omega=4 \times 10^{10} \mathrm{rad} / \mathrm{s}:\left(\right.\) a) \(\alpha_{\text {Tef }} / \alpha_{\text {brass }} ;(b) \lambda_{\text {Tef }} / \lambda_{\text {brass }} ;\) (c) \(v_{\text {Tef }} / v_{\text {brass }}\).

Short Answer

Expert verified
Question: Calculate the ratios of (a) attenuation constant, (b) wavelength, and (c) phase velocity for Teflon and brass at the given angular frequency \(\omega\). Answer: (a) \(\alpha_{\text {Tef }} / \alpha_{\text {brass }} = \text {(Ratio calculated from Step 5)}\) (b) \(\lambda_{\text {Tef }} / \lambda_{\text {brass }} = \text {(Ratio calculated from Step 5)}\) (c) \(v_{\text {Tef }} / v_{\text {brass }} = \text {(Ratio calculated from Step 5)}\)

Step by step solution

01

Gather materials and property data

Refer to Appendix C for the properties of Teflon and brass. The important values are permittivity (\(\epsilon\)), permeability (\(\mu\)), and conductivity (\(\sigma\)) for both materials.
02

Compute intrinsic impedances and propagation constants

Firstly, we need to compute the intrinsic impedance (\(\eta\)) and the propagation constant (\(\gamma\)) for Teflon and brass. The formulas for intrinsic impedance and propagation constant are: \(\eta=\sqrt{\frac{j \omega \mu}{\sigma+j \omega \epsilon}}\) \(\gamma=\sqrt{j \omega \mu(\sigma+j \omega \epsilon)}\) Substitute the given values of \(\omega\), \(\epsilon\), \(\mu\), and \(\sigma\) for both Teflon and brass to compute the intrinsic impedances and propagation constants.
03

Find the attenuation constants and wavelengths

The propagation constant \(\gamma\) has real and imaginary parts. The real part is the attenuation constant (\(\alpha\)), and the imaginary part is the phase constant (\(\beta\)). Obtain \(\alpha\) and \(\beta\) for both Teflon and brass. Now, calculate the wavelength (\(\lambda\)) using the formula: \(\lambda=\frac{2\pi}{\beta}\) Compute the wavelength for both Teflon and brass.
04

Calculate phase velocities

Next, we need to find the phase velocity (\(v\)) for Teflon and brass. The phase velocity can be calculated using the formula: \(v=\frac{\omega}{\beta}\) Compute the phase velocity for both Teflon and brass.
05

Find the required ratios

Finally, calculate the required ratios: (a) \(\alpha_{\text {Tef }} / \alpha_{\text {brass }}\) (b) \(\lambda_{\text {Tef }} / \lambda_{\text {brass }}\) (c) \(v_{\text {Tef }} / v_{\text {brass }}\) Using the previously computed values of \(\alpha\), \(\lambda\), and \(v\) for Teflon and brass, find the respective ratios.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A A \(2 \mathrm{GHz}\) uniform plane wave has an amplitude \(E_{y 0}=1.4 \mathrm{kV} / \mathrm{m}\) at \((0,0,0,\), \(t=0\) ) and is propagating in the \(\mathbf{a}_{z}\) direction in a medium where \(\epsilon^{\prime \prime}=1.6 \times\) \(10^{-11} \mathrm{~F} / \mathrm{m}, \epsilon^{\prime}=3.0 \times 10^{-11} \mathrm{~F} / \mathrm{m}\), and \(\mu=2.5 \mu \mathrm{H} / \mathrm{m}\). Find \((\) a \() E_{y}\) at \(P(0,0,1.8 \mathrm{~cm})\) at \(0.2 \mathrm{~ns} ;(b) H_{x}\) at \(P\) at \(0.2 \mathrm{~ns}\).

Small antennas have low efficiencies (as will be seen in Chapter 14 ), and the efficiency increases with size up to the point at which a critical dimension of the antenna is an appreciable fraction of a wavelength, say \(\lambda / 8 .(a) \mathrm{An}\) antenna that is \(12 \mathrm{~cm}\) long is operated in air at \(1 \mathrm{MHz}\). What fraction of a wavelength long is it? \((b)\) The same antenna is embedded in a ferrite material for which \(\epsilon_{r}=20\) and \(\mu_{r}=2,000\). What fraction of a wavelength is it now?

Let \(\eta=250+j 30 \Omega\) and \(j k=0.2+j 2 \mathrm{~m}^{-1}\) for a uniform plane wave propagating in the \(\mathbf{a}_{z}\) direction in a dielectric having some finite conductivity. If \(\left|E_{s}\right|=400 \mathrm{~V} / \mathrm{m}\) at \(z=0\), find \((a)\langle\mathbf{S}\rangle\) at \(z=0\) and \(z=60\) \(\mathrm{cm} ;(b)\) the average ohmic power dissipation in watts per cubic meter at \(z=60 \mathrm{~cm} .\)

Consider a left circularly polarized wave in free space that propagates in the forward \(z\) direction. The electric field is given by the appropriate form of Eq. (100). Determine ( \(a\) ) the magnetic field phasor, \(\mathbf{H}_{s} ;(b)\) an expression for the average power density in the wave in \(\mathrm{W} / \mathrm{m}^{2}\) by direct application of Eq. (77).

Given a wave for which \(\mathbf{E}_{s}=15 e^{-j \beta z} \mathbf{a}_{x}+18 e^{-j \beta z} e^{j \phi} \mathbf{a}_{y} \mathrm{~V} / \mathrm{m}\) in a medium characterized by complex intrinsic impedance, \(\eta(a)\) find \(\mathbf{H}_{s} ;(b)\) determine the average power density in \(\mathrm{W} / \mathrm{m}^{2}\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free