Find \(R, L, C\), and \(G\) for a two-wire transmission line in polyethylene at \(f=800 \mathrm{MHz}\). Assume copper conductors of radius \(0.50 \mathrm{~mm}\) and separation \(0.80 \mathrm{~cm}\). Use \(\epsilon_{r}=2.26\) and \(\sigma /\left(\omega \epsilon^{\prime}\right)=4.0 \times 10^{-4}\).

Question: Calculate the transmission line parameters (Resistance, Inductance, Capacitance, and Conductance per unit length) for a two-wire transmission line, given the following information: - Frequency: \(800\) MHz - Radius of copper conductors: \(0.50\) mm - Separation between conductors: \(0.80\) cm - Relative permittivity of polyethylene: \(2.26\) - Loss tangent value: \(\frac{\sigma}{\omega \epsilon'} = 4.0 \times 10^{-4}\) Answer: The transmission line parameters are as follows: 1. Resistance per unit length (R): \(0.00683 \, \Omega/m\) 2. Inductance per unit length (L): \(3.65 \times 10^{-7} \, H/m\) 3. Capacitance per unit length (C): \(2.37\times 10^{-11} \, F/m\) 4. Conductance per unit length (G): \(4.63\times 10^{-12} \, S/m\)