The expression \(\tan \theta \sec \theta\left(1-\sin ^{2} \theta\right) / \cos \theta \operatorname{simplifies~to~}\) a) \(\sin \theta\) b) \(\cos \theta\) c) \(\tan \theta\) d) \(\sec \theta\)

Short Answer

Expert verified
Question: Simplify the expression \(\frac{\tan \theta \sec \theta\left(1-\sin ^{2} \theta\right)}{\cos \theta}\). Answer: \(\tan \theta\)

Step by step solution

01

Write down the given expression

The given expression is: $$ \frac{\tan \theta \sec \theta\left(1-\sin ^{2} \theta\right)}{\cos \theta} $$
02

Replace the tan and sec functions using their definition

We know that \(\tan \theta = \frac{\sin \theta}{\cos \theta}\) and \(\sec \theta = \frac{1}{\cos \theta}\), so we can rewrite the expression as: $$ \frac{\frac{\sin \theta}{\cos \theta} \cdot \frac{1}{\cos \theta}\left(1-\sin ^{2} \theta\right)}{\cos \theta} $$
03

Simplify the fraction

Multiply the numerators, which results in: $$ \frac{\sin \theta (1-\sin ^{2} \theta)}{\cos ^{3} \theta} $$
04

Use the Pythagorean identity

We know that \(\sin^2\theta + \cos^2\theta = 1\), so \(1 - \sin^2\theta = \cos^2\theta\). Replace in the expression: $$ \frac{\sin \theta \cdot \cos^2 \theta}{\cos ^{3} \theta} $$
05

Simplify the expression

Cancel \(\cos^2\theta\) from the numerator and denominator, leaving us with: $$ \frac{\sin \theta}{\cos \theta} $$
06

Rewrite the expression using trigonometric functions

We can rewrite the expression back to the tangent function: $$ \tan \theta $$ The simplified expression is \(\tan \theta\), which corresponds to option c) in the exercise.

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