Three equal masses \(m\) are located at the vertices of an equilateral triangle of side \(L,\) connected by rods of negligible mass. Find expressions for the rotational inertia of this object (a) about an axis through the center of the triangle and perpendicular to its plane and (b) about an axis that passes through one vertex and the midpoint of the opposite side.

Short Answer

Expert verified
The rotational inertia about an axis through the center of the triangle (a) is \(m*L^2/4\), and about an axis passing through one vertex and the midpoint of the opposite side (b) is \(m*L^2/2\).

Step by step solution

01

Understand and apply principles of rotational inertia

Masses at the vertices of the triangle can be seen as point masses. Rotational inertia of a system of the point masses is just the sum of the moment of inertia of each individual point mass. The moment of inertia of a point mass is \(I = m*r^2\), where \(m\) is the mass and \(r\) is the distance of the point mass from the axis of rotation. In this scenario, for (a), the axis of rotation is through the center of the triangle, thus \(r\) would be the distance from each mass to the center of the triangle.
02

Identify requirements for equilateral triangle

Use the formula of the centroid of an equilateral triangle. The centroid (G) of an equilateral triangle with a side length \(L\) lies a distance of \(r = L/(2*\sqrt{3})\) from each vertex.
03

Calculate rotational inertia (a)

After substituting \(r = L/(2*\sqrt{3})\) into equation of moment of inertia, then multiply the result by 3 (because there are 3 masses), the rotational inertia about an axis through the center of the triangle \(I_G\) is given as \(I_G = 3*m*(L/(2*\sqrt{3}))^2 = m*L^2/4\).
04

Identify requirements for axis passing through vertex

For (b), consider that the axis of rotation passes through one vertex and the midpoint of the opposite side. Here, one of the masses is on the axis of rotation and thus contributes nothing to the rotational inertia. The other two masses are at a distance of \(L/2\) from the axis.
05

Calculate rotational inertia (b)

After substituting \(r = L/2\) into equation of moment of inertia, then multiply the result by 2 (because there are 2 masses contribute to the rotational inertia), the rotational inertia about an axis passing through one vertex and the midpoint of the opposite side \(I_V\) is given as \(I_V = 2*m*(L/2)^2 = m*L^2/2\).

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