Full-circle rotation is common in mechanical systems, but less evident in biology. Yet many single-celled organisms are propelled by spinning, tail-like flagella. The Flagellum of the bacterium \(E\) coli spins at some 600 rad/s, propelling the bacterium at speeds around \(25 \mu \mathrm{m} / \mathrm{s}\). How many revolutions does \(E .\) coli's flagellum make as the bacterium crosses a microscope's \(150-\mu \mathrm{m}-\) wide field of view?

Short Answer

Expert verified
The flagellum of E. coli makes approximately 573 revolutions as the bacterium crosses a microscope's 150-micrometer-wide field of view.

Step by step solution

01

Calculate time taken to cross the field of view

First, find out how long it takes for E. coli to cross the field of view. This can be done by dividing the distance across the field of view (150µm) by the speed of E. coli (25µm/s): \( \frac{150\mu m}{25\mu m/s} = 6s \)
02

Determine the number of rotations

Next, calculate the number of rotations made by the flagellum during this time. As the flagellum spins at 600 rad/s and for one full circle the angle in radian is \(2\pi\), the rotations per second is \( \frac{600rad/s}{2 \pi} \). The total number of rotations in 6 seconds is \( \frac{600rad/s}{2 \pi} * 6s = 573 \) rotations approximately.

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