A solid sphere and a solid cube have the same mass, and the side of the cube is equal to the diameter of the sphere. The cube's rotation axis is perpendicular to two of its faces. Which has greater rotational inertia about an axis through the center of mass?

Short Answer

Expert verified
The solid sphere has a greater rotational inertia about an axis through the center of mass than the solid cube, given that they have the same mass and the side length of the cube is equal to the diameter of the sphere.

Step by step solution

01

Formula for the sphere's rotational inertia

Start by writing down the formula for a sphere's rotational inertia: \( I_{sphere} = (2/5)mr^2 \). Here, replace \( r \) with \( L/2 \), giving \( I_{sphere} = (2/5)m(L/2)^2 \). This simplifies to \( I_{sphere} = (1/5)mL^2 \).
02

Formula for the cube's rotational inertia

Now, write down the formula for a cube's rotational inertia: \( I_{cube} = (1/6)mL^2 \).
03

Compare the rotational inertia

Finally, compare the rotational inertia of the two shapes. From the equations, we can see that \( I_{sphere} = (1/5)mL^2 \) and \( I_{cube} = (1/6)mL^2 \). As 1/5 is greater than 1/6, the sphere has the greater rotational inertia.

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