Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 13: Problem 21

A hummingbird's wings vibrate at about \(45 \mathrm{Hz}\). What's the corresponding period?

Short Answer

Expert verified
The period of the hummingbird's wing vibrations is \(1/45\) seconds or approximately 0.022 seconds.

Step by step solution

01

Identify the Given Values

The frequency \(f\) of the hummingbird's wing vibrations is given as \(45 \mathrm{Hz}\). This is the only value given in the problem, so it is what you will use to solve.
02

Use the Formula for Period

We use the formula for period, which is \(T = 1/f\), where \(f\) is the frequency. Substitute \(45 \mathrm{Hz}\) for \(f\) in the formula.
03

Compute the period

After substituting the given frequency into the formula, you calculate the period \(T\), which is the solution to the problem.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

When in its cycle is the acceleration of an undamped simple harmonic oscillator zero? When is the velocity zero?

A massless spring with \(k=74 \mathrm{N} / \mathrm{m}\) hangs from the ceiling. A \(490-\mathrm{g}\) mass is hooked onto the unstretched spring and allowed to drop. Find (a) the amplitude and (b) the period of the resulting

A wheel rotates at 600 rpm. Viewed from the edge, a point on the wheel appears to undergo simple harmonic motion. What are (a) the frequency in \(\mathrm{Hz}\) and (b) the angular frequency for this SHM?

At the heart of a grandfather clock is a simple pendulum \(1.45 \mathrm{m}\) long; the clock ticks each time the pendulum reaches its maximum displacement in either direction. What's the time interval between ticks?

The quartz crystal in a watch executes simple harmonic motion at \(32,768 \mathrm{Hz}\) (This is \(2^{15} \mathrm{Hz}\), chosen so that 15 divisions by 2 give a signal at \(1.00000 \mathrm{Hz}\) ) If each face of the crystal undergoes a maximum displacement of \(100 \mathrm{nm}\), find the maximum velocity and acceleration of the crystal faces.
See all solutions

Recommended explanations on Physics Textbooks

Energy Physics

Read Explanation

Scientific Method Physics

Read Explanation

Geometrical and Physical Optics

Read Explanation

Fluids

Read Explanation

Particle Model of Matter

Read Explanation

Engineering Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free