Chapter 17: Problem 12
Why do we use the triple point of water for thermometer calibration? Why not just use the melting point or boiling point?
Chapter 17: Problem 12
Why do we use the triple point of water for thermometer calibration? Why not just use the melting point or boiling point?
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Get started for freeHow many molecules are in an ideal-gas sample at \(350 \mathrm{K}\) that occupies \(8.5 \mathrm{L}\) when the pressure is \(180 \mathrm{kPa} ?\)
A solar-heated house stores energy in 5.0 tons of Glauber salt \(\left(\mathrm{Na}_{2} \mathrm{SO}_{4} \cdot 10 \mathrm{H}_{2} \mathrm{O}\right),\) which melts at \(90^{\circ} \mathrm{F} .\) The heat of fusion of\ Glauber salt is 104 Btu/lb and the specific heats of the solid and liquid are, respectively, \(0.46 \mathrm{Btu} / \mathrm{lb} \cdot^{\circ} \mathrm{F}\) and \(0.68 \mathrm{Btu} / \mathrm{lb} \cdot^{\circ} \mathrm{F}\) After a week of sunny weather, the storage medium is all liquid at \(95^{\circ} \mathrm{F} .\) Then comes a cloudy period during which the house loses heat at an average of 20,000 Btu/h. (a) How long is it before the temperature of the storage medium drops below \(60^{\circ} \mathrm{F} ?\) (b) How much of this time is spent at \(90^{\circ} \mathrm{F} ?\)
Two different gases are at the same temperature, and both have low enough densities that they behave like ideal gases. Do their molecules have the same thermal speeds? Explain.
Water's coefficient of volume expansion in the temperature range from \(0^{\circ} \mathrm{C}\) to about \(20^{\circ} \mathrm{C}\) is given approximately by \(\beta=a+b T+c T^{2},\) where \(T\) is in Celsius and \(a=-6.43 \times\) \(10^{-5} \circ C^{-1}\) \(b=1.70 \times 10^{-5} \cdot \mathrm{C}^{-2}\) and \(c=-2.02 \times 10^{-7} \mathrm{c}^{-3}\) Show that water has its greatest density at approximately \(4.0^{\circ} \mathrm{C}\)
Which takes more heat: melting a gram of ice already at \(0^{\circ} \mathrm{C},\) or bringing the melted water to the boiling point?
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