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Chapter 19: Problem 2

Could you heat the kitchen by leaving the oven open? Explain.

Short Answer

Expert verified
While an open oven will release heat into the room and may lead to a small increase in temperature, it is an inefficient and potentially unsafe way to heat a kitchen.

Step by step solution

01

Understand the heat transfer method

The first step is to understand that heat is transferred primarily through three different methods; conduction, convection and radiation. In the case of an oven and its impact on the kitchen environment, we would be mainly dealing with convection. Convection is the heat transfer due to the bulk movement of molecules within fluids such as gases and liquids.
02

Apply the method to the problem

When the oven is open, the heat inside it will start to spread out into the room. This is because of the principle that heat always moves from areas of high temperature to areas of low temperature. This movement of heat will speed up if the difference in temperature between the two areas is significant. In this case, the heat starts to flow from the oven into the room, which will cause the room temperature to rise, at least in the vicinity of the oven.
03

Consider practical aspects

However it is important to note that while theoretically, an open oven can heat a room to some degree, it is not efficient or safe. The manner in which heat is lost from the oven is not controlled and energy is wasted. Further, operating an oven with the door open may also result in a safety hazard.

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Most popular questions from this chapter

Why doesn't the evolution of human civilization violate the second law of thermodynamics?

An object's heat capacity is inversely proportional to its absolute temperature: \(C=C_{0}\left(T_{0} / T\right),\) where \(C_{0}\) and \(T_{0}\) are constants. Find the entropy change when the object is heated from \(T_{0}\) to \(T_{1}\).

A Carnot engine absorbs \(900 \mathrm{J}\) of heat each cycle and provides \(350 \mathrm{J}\) of work. (a) What's its efficiency? (b) How much heat is rejected each cycle? (c) If the engine rejects heat at \(10^{\circ} \mathrm{C},\) what's its maximum temperature?

Problem 74 of Chapter 16 provided an approximate expression for the specific heat of copper at low absolute temperatures: \(c=31(T / 343 \mathrm{K})^{3} \mathrm{J} / \mathrm{kg} \cdot \mathrm{K} .\) Use this to find the entropy change when \(40 \mathrm{g}\) of copper are cooled from \(25 \mathrm{K}\) to \(10 \mathrm{K}\). Why is the change negative?

Use energy-flow diagrams to show that the existence of a perfect heat engine would permit the construction of a perfect refrigerator, thus violating the Clausius statement of the second law.
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