You're the environmental protection officer for a \(35 \%\) efficient nuclear power plant that produces 750 MW of electric power, situated on a river whose minimum flow rate is \(110 \mathrm{m}^{3} / \mathrm{s}\). State environmental regulations limit the rise in river temperature from your plant's cooling system to \(5^{\circ} \mathrm{C}\). Can you achieve this standard if you use river water for all your cooling, or will you need to install cooling towers that transfer some of your waste heat to the atmosphere?

Short Answer

Expert verified
No additional cooling towers are needed. The river's flow rate and temperature increase limitation are sufficient to cool the waste heat.

Step by step solution

01

Calculate thermal output

Firstly, calculate the total thermal power output of the power plant. Since the power plant is 35% efficient, this means that 65% of the power produced is wasted thermal energy. This can be calculated using the equation: Total Power output = Electric Power / Efficiency . Therefore, the Total Power Output equals to 750 MW / 0.35 = 2142.86 MW.
02

Calculate waste heat

Now, calculate the waste heat output of the power plant. This is done by subtracting the electrical power generated by the power plant from the total power output. So, the waste heat is 2142.86 MW - 750 MW = 1392.86 MW.
03

Calculate the heat capacity of the river

Now, calculate the maximum amount of heat that the river can absorb without its temperature rising beyond the permissible limit. The amount of heat that can be absorbed by the river water can be calculated using the equation: Q = mcΔT, where m is the mass of water (which can be calculated from the flow rate of the river and the density of water), c is the specific heat capacity of water and ΔT is the change in temperature. Assuming the value of c to be 4.18 kJ/(kg°C), and the density of water as 1000 kg/m³, The mass flow rate can be found using the equation: mass flow rate = flow rate * density of water. This equals to 110 m³/s * 1000 kg/m³ = 110000 kg/s. Substituting in the previous equation, the heat absorbed by the river equals to 110000 kg/s * 4.18 kJ/(kg°C) * 5°C = 2297000 kW or 2297 MW.
04

Compare the heat output and the heat capacity of the river

Compare the waste heat output from the power plant with the heat capacity of the river. If the waste heat output is less than or equal to the heat capacity of the river, then the power plant can use river water for cooling without violating environmental regulations. If the waste heat output is greater, then the power plant should use cooling towers. In this case, the waste heat output of 1392.86 MW is less than the heat capacity of the river (2297 MW), therefore no additional cooling towers are needed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Thermal Power Output Calculation
Understanding the thermal power output of a power plant is crucial in determining its overall efficiency and environmental impact. In simple terms, thermal power output is the total amount of heat energy produced by the power plant. For a nuclear plant, this energy comes from nuclear reactions and is used to generate steam, which then drives turbines to produce electricity.

The efficiency of a power plant is the ratio of the useful electrical power output to the total thermal energy input. Knowing that our example nuclear power plant operates at 35% efficiency tells us that 35% of the heat produced is converted into electrical energy, while the remaining 65% is waste heat that needs to be managed.

To calculate the thermal power output, we use the equation \( \text{Total Power Output} = \frac{\text{Electric Power}}{\text{Efficiency}} \). From our example, a power plant producing 750 MW of electric power at 35% efficiency results in a total thermal power output of approximately 2142.86 MW. Managing this waste heat is vital to prevent detrimental impacts on the environment, which leads to the implementation of cooling systems like river water or cooling towers.
Environmental Regulations for Power Plants
Power plants are subject to a variety of environmental regulations to mitigate their impact on the surrounding environment. These regulations often concern emissions, waste management, and specifically for nuclear power plants, the thermal pollution of water bodies used for cooling.

In our scenario, the environmental regulations stipulate that the rise in river temperature due to the plant's cooling system must not exceed 5 degrees Celsius. This constraint is critical for protecting aquatic life, as temperature increases can have harmful effects on river ecosystems, such as reducing oxygen levels and altering species composition.

Therefore, power plants are required to design their cooling systems—whether they use once-through, recirculating systems with cooling towers, or dry-cooling technologies—to adhere to these temperature limits. Understanding these regulations is fundamental for environmental protection officers, and they are a key factor in the decision-making process for the type of cooling system a power plant will employ.
Heat Capacity of River
The heat capacity of a river is a measure of how much heat the river water can absorb before its temperature changes. Rivers often serve as natural heat sinks for thermal power plants, but there's a limit to how much heating a river can sustain without ecological damage.

To calculate the heat absorption capacity of a river, one critical aspect is the mass flow rate of the river, which derives from the volume flow rate (\(110 \mathrm{m}^3/\text{s}\) in our example) and the density of water. Using the mass flow rate (\(110000 \text{kg/s}\) in this case), the specific heat capacity of water (\(4.18 \text{kJ/(kg°C)}\)), and the permissible temperature rise (\(5^\circ \text{C}\)), we find that the river's heat absorption capacity is about 2297 MW.

This capacity indicates whether the river can handle the waste heat from the power plant without the temperature rising above regulatory limits. If a power plant's waste thermal output is within this capacity, as in our example where it produces 1392.86 MW of waste heat, the river can be used for cooling without the need for additional cooling towers.

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