A giant eruption on the Sun propels solar material from rest to \(450 \mathrm{km} / \mathrm{s}\) over a period of \(1 \mathrm{h} .\) Find the average acceleration.

Short Answer

Expert verified
The average acceleration is \(125\) m/s².

Step by step solution

01

Understanding the Given Information

First, let's understand our known variables. The two most crucial details provided in the problem are the final speed of 450 km/s and the time it took for this speed to be reached, which is 1 hour.
02

Conversion Into Standard Units

To solve physics problems, it's essential to work with standard units. Convert 450 km/s to m/s by multiplying it by 1000 (since 1 km is equal to 1000 m), we get \(450,000\) m/s. Convert the time of 1 hour to seconds since the standard unit of time in physics is seconds. 1 hour equals 3600 seconds.
03

Applying the Acceleration Formula

The formula for acceleration is \(\frac{Final \ Velocity - Initial \ Velocity}{Time}\). It was stated that the solar material started from rest, which means that the initial speed was zero. So, plug in the given values: \(\frac{450,000 \ m/s - 0 \ m/s}{3600 \ s}\)
04

Calculating the Average Acceleration

Divide 450,000 m/s by 3600 s. This gives an average acceleration of \(125\) m/s².

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