Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 2: Problem 24

A space shuttle's main engines cut off 8.5 min after launch, at which time its speed is \(7.6 \mathrm{km} / \mathrm{s} .\) What's the shuttle's average acceleration during this interval?

Short Answer

Expert verified
The average acceleration of the space shuttle is \(0.0149 \, \mathrm{km/s^2}\)

Step by step solution

01

Identify the Given Parameters

First, we're given the final velocity \(v = 7.6 \, \mathrm{km/s}\), the initial velocity \(u = 0 \, \mathrm{km/s}\) (assuming the shuttle starts from rest), and the time \(t = 8.5 \, \mathrm{minutes}\). Convert the time into seconds: \(t = 8.5 \, \mathrm{min} \times 60 \, \mathrm{s/min} = 510 \, \mathrm{s}\).
02

Calculate the Average Acceleration

We apply the formula for acceleration, which is change in velocity over change in time. In this case, it would be \(a = (v - u) / t\). Plugging in the given values, we get: \(a = (7.6 \, \mathrm{km/s} - 0 \, \mathrm{km/s}) / 510 \, \mathrm{s} = 0.0149 \, \mathrm{km/s^2}\). This is the average acceleration of the space shuttle during engine operation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An object's position is given by \(x=b t^{3},\) with \(x\) in meters, \(t\) in seconds, and \(b=1.5 \mathrm{m} / \mathrm{s}^{3} .\) Determine (a) the instantaneous velocity and (b) the instantaneous acceleration at the end of \(2.5 \mathrm{s}\) Find (c) the average velocity and (d) the average acceleration during the first \(2.5 \mathrm{s}\)

What's the conversion factor from meters per second to miles per hour?

A particle's position as a function of time is given by \(x=x_{0} \sin \omega t,\) where \(x_{0}\) and \(\omega\) are constants. (a) Find expressions for the velocity and acceleration. (b) What are the maximum values of velocity and acceleration? (Hint: Consult the table of derivatives in Appendix A.)

An egg drops from a second-story window, taking 1.12 s to fall and reaching \(11.0 \mathrm{m} / \mathrm{s}\) just before hitting the ground. On contact, the egg stops completely in 0.131 s. Calculate the average magnitudes of its acceleration while falling and while stopping.

An object's position as a function of time \(t\) is given by \(x=b t^{4}\) with \(b\) a constant. Find an expression for the instantaneous velocity, and show that the average velocity over the interval from \(t=0\) to any time \(t\) is one- fourth of the instantaneous velocity at \(t\)
See all solutions

Recommended explanations on Physics Textbooks

Medical Physics

Read Explanation

Radiation

Read Explanation

Famous Physicists

Read Explanation

Waves Physics

Read Explanation

Space Physics

Read Explanation

Fluids

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free