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Chapter 20: Problem 22

Find the magnitude of the electric force on a \(2.0-\mu \mathrm{C}\) charge in a \(100-\mathrm{N} / \mathrm{C}\) electric field.

Short Answer

Expert verified
The magnitude of the electric force on a 2.0-μC charge in a 100-N/C electric field is \(0.2 N\).

Step by step solution

01

Identify given variables

The given variables are the charge (\(Q = 2.0\mu C\)) and the electric field (\(E = 100N/C\)). We must convert the charge from microcoulombs to coulombs by multiplying by \(1x10^{-6}\). So, the charge is \(2.0 \times 10^{-6} C\).
02

Use Coulomb's Law to find electric force

Coulomb's Law is stated as: \(F = QE\), where \(F\) is the electric force, \(Q\) is the charge, and \(E\) is the electric field. Plugging in the values: \(F = (2.0 \times 10^{-6} C)(100 N/C)\)
03

Compute for electric force

By multiplying the given values, the electric force on the charge is \(0.2 N\).

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