Chapter 22: Problem 25
The potential at the surface of a 10 -cm-radius sphere is \(4.8 \mathrm{kV}\) What's the sphere's total charge, assuming charge is distributed in a spherically symmetric way?
Chapter 22: Problem 25
The potential at the surface of a 10 -cm-radius sphere is \(4.8 \mathrm{kV}\) What's the sphere's total charge, assuming charge is distributed in a spherically symmetric way?
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Get started for freeYou're sizing a new electric transmission line, and you can save money with thinner wire. The potential difference between the line and the ground, \(60 \mathrm{m}\) below, is \(115 \mathrm{kV}\). The field at the wire surface cannot exceed \(25 \%\) of the 3 -MV/m breakdown field in air. Neglecting charges in the ground itself, what minimum wire diameter do you specify? (Hint. You'll have to do a numerical calculation.)
Three equal charges \(q\) form an equilateral triangle of side \(a\). Find the potential at the center of the triangle.
Two identical charges \(q\) lie on the \(x\) -axis at \(\pm a\). (a) Find an expression for the potential at all points in the \(x\) -y plane. (b) Show that your result reduces to the potential of a point charge for distances large compared with \(a\).
A solid sphere contains positive charge uniformly distributed throughout its volume. Is the potential at its center higher than, lower than, or the same as at the surface?
In a uniform electric field, equipotential planes that differ by \(1.0 \mathrm{V}\) are \(2.5 \mathrm{cm}\) apart. What's the field strength?
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