Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 23: Problem 21

A capacitor's plates hold \(1.3 \mu \mathrm{C}\) when charged to \(60 \mathrm{V}\). What's its capacitance?

Short Answer

Expert verified
The capacitance of the capacitor is \(2.167 \times 10^{-8} \mathrm{F}\).

Step by step solution

01

Identify the given parameters

The charged stored (\(Q\)) is \(1.3 \mu \mathrm{C} = 1.3 \times 10^{-6} \mathrm{C}\) and the potential difference (\(V\)) is \(60 \mathrm{V}\).
02

Apply the formula of capacitance

The formula to calculate capacitance (\(C\)) is \(C = Q/V\). Substitute \(Q\) as \(1.3 \times 10^{-6} \mathrm{C}\) and \(V\) as \(60 \mathrm{V}\) into the equation.
03

Calculate Capacitance

After applying the values into the formula, \(C = 1.3 \times 10^{-6} \mathrm{C} / 60 \mathrm{V} = 2.167 \times 10^{-8} \mathrm{F}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Your company is still stuck with those 2 - \(\mu\) F capacitors from Problem 50. They turn out to be so cheap that their capacitances are all too low, ranging from \(1.7 \mu \mathrm{F}\) to \(1.9 \mu \mathrm{F}\). A colleague suggests you put variable "trimmer" capacitors in parallel with the cheap capacitors and adjust the combination to precisely \(2.00 \mu \mathrm{F} .\) The available trimmers have variable capacitance from \(25 \mathrm{nF}\) to \(350 \mathrm{nF}\). Will they work?

A capacitor consists of square conducting plates \(25 \mathrm{cm}\) on a side and \(5.0 \mathrm{mm}\) apart, carrying charges \(\pm 1.1 \mu \mathrm{C}\). Find (a) the electric field, (b) the potential difference between the plates, and (c) the stored energy.

A sphere of radius \(R\) contains charge \(Q\) spread uniformly throughout its volume. Find an expression for the electrostatic energy contained within the sphere itself. (Hint: Consult Example 21.1.)

The potential difference across a cell membrane is \(65 \mathrm{mV}\). On the outside are \(1.5 \times 10^{6}\) singly ionized potassium atoms. Assuming an equal negative charge on the inside, find the membrane's capacitance.

Show that the units of \(\epsilon_{0}\) may be written as \(\mathrm{F} / \mathrm{m}\).
See all solutions

Recommended explanations on Physics Textbooks

Electromagnetism

Read Explanation

Electrostatics

Read Explanation

Magnetism

Read Explanation

Geometrical and Physical Optics

Read Explanation

Atoms and Radioactivity

Read Explanation

Mechanics and Materials

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free