The "memory" capacitor in a video recorder stores program recording information during power outages. It has capacitance \(4.0 \mathrm{F}\) and is charged to \(3.5 \mathrm{V} .\) What's the charge on its plates?

Short Answer

Expert verified
The charge on the capacitor's plates is \(14 \mathrm{C}\).

Step by step solution

01

Understand the Given Parameters

The given parameters are Capacitance, \(C = 4.0 \mathrm{F}\) and Voltage, \(V = 3.5 \mathrm{V}\). We need to find the charge on the capacitor's plates, denoted as \(Q\).
02

Apply the charge formula

The basic relationship between charge, capacitance, and voltage is given by the formula: \(Q = CV\). This means Charge equals Capacitance times Voltage.
03

Calculate the Charge

Substitute the given values into the formula from Step 2: \(Q = 4.0 \mathrm{F} \times 3.5 \mathrm{V}\).
04

Solve the Expression

On performing the multiplication, the value of \(Q\) comes out to be \(14 \mathrm{C}\) (Coulombs).

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