What's the current in a 47-k.\Omega resistor with \(110 \mathrm{V}\) across it?

Short Answer

Expert verified
The current flowing through the resistor is \(0.00234 \mathrm{A}\) or \(2.34 \mathrm{mA}\).

Step by step solution

01

Convert kilo-ohm to ohm

In this step, convert the resistance from kilo-ohm to ohm by multiplying it by \(1000\). So, the resistance in ohms will be \(47 k. \Omega * 1000 = 47000 \Omega\).
02

Apply Ohm's law

Plug the voltage and resistance into Ohm’s Law to find the current. So, \(I = \frac{V}{R} = \frac{110 \mathrm{V}}{47000 \Omega}\).
03

Perform calculations

After plugging the values into the equation, perform the division to find the current. The result is \(0.00234 \mathrm{A}\) or \(2.34 \mathrm{mA}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ohm's Law Calculations
Ohm's Law is a fundamental principle in the field of electronics and electrical engineering. It defines the relationship between voltage, current, and resistance in an electrical circuit. The mathematical expression of Ohm's Law is given by the formula:
\[ I = \frac{V}{R} \]
where:
  • \( I \) is the current in amperes (A),
  • \( V \) is the voltage in volts (V),
  • \( R \) is the resistance in ohms (\( \Omega \)).

Using Ohm's Law to calculate any one of these quantities requires the other two to be known. For example, if you wish to find the current (\( I \)) flowing through a component, you would need to know the voltage across the component and its resistance, as outlined in the exercise provided.
In more complex circuits with multiple resistors and power sources, Ohm's Law can be applied individually to each component or in combination with other circuit analysis techniques, such as Kirchhoff's circuit laws. Understanding how to calculate these relationships is essential for designing, analyzing, and troubleshooting electrical circuits.
Electrical Resistance Conversion
In practical scenarios, resistance values may be presented in units other than ohms. For instance, it is common to encounter resistors labeled in kilo-ohms (\( k\Omega \)) or mega-ohms (\( M\Omega \)). Conversion between these units is crucial for accurate calculations.
To convert from kilo-ohms to ohms, as demonstrated in the step-by-step solution, you simply multiply the number of kilo-ohms by \(1000\):
\[ 1 k\Omega = 1000 \Omega \]
Similarly, to convert from mega-ohms to ohms, you would multiply by \(1,000,000\):
\[ 1 M\Omega = 1,000,000 \Omega \]
This conversion is an essential step before applying Ohm's Law since it ensures that all quantities are expressed in compatible units for the calculations. Always remember to check the units of each measurement and convert where necessary to avoid errors in your calculations.
Current in a Resistor
Current is the rate at which charge flows through a conductor, and in a resistor, current depends on the voltage applied across it and the resistance it provides. The 'current in a resistor', therefore, refers to the amount of electric current that flows through the resistor due to the potential difference (voltage) across its terminals.
When you apply Ohm's Law, as seen in the problem's solution, you find that a higher resistance results in a lower current for a given voltage. This is reflective of the nature of a resistor, which is to oppose or resist the flow of current. It's important to note that the current calculated is the direct (DC) or steady-state current in the case of direct voltage being applied.
For alternating currents (AC), where voltages change over time, the concept still applies, but the effective or root-mean-square (RMS) values of voltage and current should be used. Calculating the current in a resistor is a fundamental skill in circuit analysis, and grasping this will help you understand how different components in a circuit influence the overall behavior of the electrical flow.

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Most popular questions from this chapter

Though rare, electrocution has been reported under wet conditions with voltages as low as \(30 \mathrm{V}\). What resistance would be necessary for this voltage to drive a fatal current of \(100 \mathrm{mA} ?\)

In a study of proteins mediating cell membrane transport, biologists measure current versus time through the cell membranes of oocytes (nearly mature egg cells) taken from the African clawed frog, Xenopus. The measured current versus time is given approximately by \(I=60 t+200 t^{2}+4.0 t^{3}\) with \(t\) in seconds and I in nA. Find the total charge that flows through the cell membrane in the interval from \(t=0\) to \(t=5.0 \mathrm{s}.\)

A \(35-\Omega\) electric stove burner consumes \(1.5 \mathrm{kW}\) of power. At what voltage does it operate?

You're writing the instruction manual for a power saw, and you have to specify the maximum permissible length for an extension cord made from 18 -gauge copper wire (diameter \(1.0 \mathrm{mm}\) ). The saw draws \(7.0 \mathrm{A}\) and needs a minimum of \(115 \mathrm{V}\) across its motor when the outlet supplies \(120 \mathrm{V}\). What do you specify for the maximum length extension cord, given that they come in 25 -foot increments?

You're heading out for spring break, but your car won't start. Your friend says you might have corrosion at the battery terminals-a frequent cause of hard starting because of increased resistance. Having read Example 24.4, you know that the resistance between battery and starter should be around \(1 \mathrm{m} \Omega\). While your friend cranks the starter, you measure \(4.2 \mathrm{V}\) between the battery terminal and the wire carrying current to the starter motor. If the motor draws \(125 \mathrm{A},\) is the resistance in its normal range?

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