Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 24: Problem 26

What current flows when a 45-V potential difference is imposed across a \(1.8-\mathrm{k} \Omega\) resistor?

Short Answer

Expert verified
The current that flows when a 45-V potential difference is imposed across a \(1.8-k\Omega\) resonance is 25 milliamperes.

Step by step solution

01

Understand the given values

The problem mentions a potential difference (V) of 45 volts and a resistance (R) of \(1.8 k\Omega\) or 1800 \(\Omega\). The task is to find the current (I).
02

Use Ohm's Law to calculate the current

Using Ohm's Law (I = V/R), plug the given values into the equation: I = 45V / 1800\(\Omega\).
03

Solve for the current

Perform the division 45V / 1800\(\Omega\) to get the value of the current which is 0.025 Amperes or 25 milliamperes.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A car's starter motor draws 125 A with 11 V across its terminals. What's its power consumption?

You touch a defective appliance while standing on the ground, and you feel the tingle of a 2.5-mA current. What's your resistance, assuming you're touching the "hot" side of the \(120-\mathrm{V}\) household wiring?

What voltage does it take to drive 300 mA through a \(1.2-\) k \(\Omega\) resistance?

A cylindrical resistor is 5.0 mm in diameter and \(1.5 \mathrm{cm}\) long. It's made of a composite material whose resistivity varies from one end to the other according to the equation \(\rho=\rho_{0}(1+x / L) e^{x / L},\) for \(0 \leq x \leq L,\) where \(\rho_{0}=2.41 \times 10^{-3} \Omega \cdot \mathrm{m} .\) Find its resistance.

A brownout occurs when an electric utility can't supply enough power to meet demand. Rather than cut off some customers completely, the utility reduces the voltage across its system. Brownouts are most likely on hot summer days, when heavy air-conditioning loads drive up demand for electricity. In a particular brownout, the utility reduces the voltage by \(10 \%.\) Which of the following occurs in the conductors of the preceding problem during the brownout? a. Both the electric field and electron drift speed decrease. b. The electric field decreases but the electron drift speed doesn't. c. The current is carried by fewer electrons. d. The electrons undergo more frequent collisions.
See all solutions

Recommended explanations on Physics Textbooks

Physical Quantities And Units

Read Explanation

Electricity and Magnetism

Read Explanation

Linear Momentum

Read Explanation

Astrophysics

Read Explanation

Electromagnetism

Read Explanation

Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free