Though rare, electrocution has been reported under wet conditions with voltages as low as \(30 \mathrm{V}\). What resistance would be necessary for this voltage to drive a fatal current of \(100 \mathrm{mA} ?\)

Short Answer

Expert verified
The necessary resistance is 300 Ohms.

Step by step solution

01

Understand Ohm's Law

Ohm's law formula is \( I = V / R \), where \( I \) is current, \( V \) is voltage and \( R \) is resistance.
02

Convert Current to Amperes

Firstly, convert the current from milliamperes to amperes. 1mA = 0.001A. So,\( I = 100mA = 0.1A \).
03

Substitute the values in the formula

By substituting the given values of voltage and current in the Ohm's law formula we get \( R = V / I \ = 30V / 0.1A \).

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