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Chapter 24: Problem 38

A gold film in an integrated circuit measures \(2.5 \mu \mathrm{m}\) thick by \(0.18 \mathrm{mm}\) wide. It carries a current density of \(0.68 \mathrm{MA} / \mathrm{m}^{2}\) What's the total current?

Short Answer

Expert verified
The total current in the gold film is \(0.306\) A

Step by step solution

01

Convert dimensions to consistent units

The dimensions of the gold film are given in different units. To make them consistent, let's convert width from mm to m: \(0.18 \mathrm{mm} = 0.18 \times 10^{-3}\) m = \(1.8 \times 10^{-4}\) m
02

Calculate area of the gold film

The area of the gold film can be calculated as height \(\times\) width. Since the film is thin, we can assume it as a rectangle. So, area = \(2.5 \times 10^{-6}\) m \(\times\) \(1.8 \times 10^{-4}\) m = \(4.5 \times 10^{-10}\) \(m^{2}\)
03

Calculate total current

The total current can be calculated by multiplying the current density by the area. Current = current density \(\times\) area = \(0.68 \times 10^{6}\) \(A/m^{2}\) \(\times\) \(4.5 \times 10^{-10}\) \(m^{2}\) = \(0.306\) A

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Most popular questions from this chapter

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