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Chapter 25: Problem 16

What's the emf of a battery that delivers \(27 \mathrm{J}\) of energy as it moves 3.0 C between its terminals?

Short Answer

Expert verified
The emf of the battery is 9 Volts.

Step by step solution

01

Understand the concept of emf

The emf (Electromotive Force) of a battery can be calculated using Joule’s law of electricity, which states that the amount of energy supplied by a source (such as a battery) is equal to the product of its emf, the quantity of charge, and the time for which the charge flows.
02

Formulate the formula for emf

With Joule's law, emf can be represented as defined by the following formula: \[ \epsilon = \frac{E}{Q} \] where \( \epsilon \) is the emf, \( E \) is the energy and \( Q \) is the charge.
03

Substitute the given values into the formula

Substituting the given values into the formula gives:\[ \epsilon = \frac{27J}{3.0C} \]
04

Calculate the emf

After performing the division, we get:\[ \epsilon = 9V \]

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