Chapter 27: Problem 24
What's the current in a 10 -mH inductor storing \(50 \mu\) J of energy?
Short Answer
Expert verified
The current in the 10 -mH inductor storing \(50 \mu\) J of energy is \(0.01\) A.
Step by step solution
01
Identify Given Values and the Required Value
The given values from the exercise are the inductance \(L = 10\) mH (millihenries) and the energy \(W = 50\) µJ (microjoules). The required value is the current (I), which we do not have.
02
Convert Units to Standard Form
The energy and inductance values should be converted to standard units - joules for energy and henries for inductance. After conversions, we have \(W = 50 × 10^{-6} = 5 × 10^{-5}\) J and \(L = 10 × 10^{-3} = 0.01\) H.
03
Substitute the Given Values into the Energy Formula
The energy stored in an inductor is described by the formula \(W = \frac{1}{2}LI^2\). We need to isolate the current (I) to solve for its value. Rearranging the formula, we get \(I = \sqrt{\frac{2W}{L}}\).
04
Calculate the Current in the Inductor
Substitute \(W = 5 × 10^{-5}\) J and \(L = 0.01\) H into the equation \(I = \sqrt{\frac{2W}{L}}\). After calculating these values, the current I obtains the value \(0.01\) A or \(10\) mA.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Energy Stored in an Inductor
When delving into the concept of how energy is stored in inductors, it's important to understand that an inductor is a passive electronic component which stores energy in its magnetic field as current flows through it. This is similar to how a capacitor stores energy in an electric field.
The energy in an inductor is given by the formula: \[\begin{equation}W = \frac{1}{2}LI^2\end{equation}\]where
The energy in an inductor is given by the formula: \[\begin{equation}W = \frac{1}{2}LI^2\end{equation}\]where
- \(W\) is the energy in joules,
- \(L\) is the inductance in henries,
- \(I\) is the current in amperes flowing through the inductor.
Inductance
Inductance, denoted as \(L\), is a fundamental property of an inductor that quantifies its ability to store magnetic energy. Inductance is determined by the physical characteristics of the inductor, such as the number of turns in the coil, the cross-sectional area of the coil, the coil length, and the type of material the core is made out of.
Factors Affecting Inductance
- The number of turns: More turns means a higher inductance.
- Cross-sectional area: A larger area results in higher inductance.
- Core material: Materials with higher magnetic permeability, such as iron, increase an inductor's inductance.
- Coil length: A shorter coil length often means greater inductance.
Standard Units Conversion
Understanding the standard units conversion is crucial for solving physics and engineering problems. In the context of our exercise, the initial values were given in millihenries (mH) for inductance and microjoules (µJ) for energy, which are not standard SI units.
To accurately calculate the current, these values needed to be converted to standard units: henries (H) for inductance and joules (J) for energy. This conversion is a matter of applying the appropriate multiplication factor:
To accurately calculate the current, these values needed to be converted to standard units: henries (H) for inductance and joules (J) for energy. This conversion is a matter of applying the appropriate multiplication factor:
- To convert millihenries (mH) to henries (H), we multiply by \(10^{-3}\) because 'milli' signifies a thousandth.
- To convert microjoules (µJ) to joules (J), we multiply by \(10^{-6}\) because 'micro' signifies a millionth.