A flip coil is used to measure magnetic fields. It's a small coil placed with its plane perpendicular to a magnetic field, and then flipped through \(180^{\circ} .\) The coil is connected to an instrument that measures the total charge \(Q\) that flows during this process. If the coil has \(N\) turns, area \(A,\) and resistance \(R,\) show that the field strength is \(B=Q R / 2 N A.\)

Short Answer

Expert verified
The magnetic field strength \( B \) is given by \( B= QR/2NA \).

Step by step solution

01

Understand and apply Faraday's Law

Start by using Faraday's law. According to Faraday's Law, the induced emf \( E \) in a closed circuit is equal to the rate of change of magnetic flux \( \Phi \) through the circuit. In mathematical term: \( E = -d\Phi/dt \)
02

Calculate total charge \( Q \)

The total charge that the instrument measures is the time integral of the current, since by definition, current \( I \) is the amount of the charge \( Q \) flowing per time \( t \). This gives: \( Q = \int Idt = \int Edt/R \), where \( R \) is the coil resistance.
03

Compute magnetic flux change \( \Delta \Phi \)

The change in magnetic flux \( \Delta \Phi \) when the coil is flipped 180 degrees is \( \Delta \Phi = 2BA \), where \( B \) is the field strength and \( A \) is the area of the coil.
04

Combine the equations

Substitute the change in magnetic flux \( \Delta \Phi \) into the equation from Step 1 giving \( E = -\Delta \Phi / \Delta t \). The EMF is also equal to \( Q / R\Delta t \) from Step 2. Setting these equal gives \( Q / R\Delta t = -\Delta \Phi / \Delta t \). Solve for \( B \) to give the final formula.

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