A \(50-\mathrm{mH}\) inductor is connected across a \(10-\mathrm{V}\) rms AC generator, and a 2.0 -mA rms current flows. What's the generator frequency?

Short Answer

Expert verified
Use steps 1 through 4 to calculate the generator frequency. Solve the equation in step 3 to get the generator frequency.

Step by step solution

01

Identify the relevant formulas

The voltage across an inductor in an AC circuit can be found using the formula \(V = I * 2 * \π * f * L\), where \(V\) is voltage, \(I\) is current, \(f\) is the frequency of the generator, and \(L\) is the inductance of the inductor. In this case, we want to solve for \(f\), so we need to rearrange the equation to give us: \(f = V / (I * 2 * \π * L)\).
02

Convert values to standard SI units

The given values are \(V = 10 V\), \(I = 2.0 mA\) and \(L = 50 mH\). We need to convert the current from mA to A by multiplying by \(10^-3\), and inductance from mH to H by multiplying by \(10^-3\). This gives us \(I = 2.0 \times 10^-3 A\) and \(L = 50 \times 10^-3 H\).
03

Substituting the given values into the rearranged formula

Now, we substitute the given values into the formula: \(f = 10 / ((2.0 \times 10^-3 A) * 2 * \π * (50 \times 10^-3 H))\)
04

Solving for the frequency

After solving the expression above, we should get the generator frequency \(f\)

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