A \(0.75-\mathrm{H}\) inductor is in series with a fluorescent lamp, and the combination is across \(120-\mathrm{V}\) rms, \(60-\mathrm{Hz}\) power. If the rms inductor voltage is \(90 \mathrm{V},\) what's the rms lamp current?

Short Answer

Expert verified
The rms lamp current is 0.318 A.

Step by step solution

01

Calculate the Total RMS Voltage

In this case, the total rms voltage across the lamp and inductor is given as 120V. This refers to the phasor sum of the rms voltage across the lamp and that across the inductor. Using the Pythagorean theorem, \(V_{lamp} = \sqrt{V_{total}^2 - V_{inductor}^2} = \sqrt{120^2 - 90^2} = 72 V\).
02

Use Ohm’s Law

The RMS current can be obtained by using Ohm's Law, which states that \(V = I \cdot Z\), where V is the voltage, I is the current and Z is the impedance. Here impedance \(Z_{inductor} = 2 \cdot \pi \cdot f \cdot L\), where \(f = 60\) Hz is the frequency, \(L = 0.75 H\) is the inductance. So, \(Z_{inductor} = 2 \cdot \pi \cdot 60 \cdot 0.75 = 282.74 \) Ohm.
03

Calculate the current

Substitute the inductor impedance and RMS voltage into Ohm's law to solve for the current: \(I = \frac{V_{inductor}}{Z_{inductor}} = \frac{90V}{282.74 \, \Omega} = 0.318 \, A\).

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