Your professor tells you about the days before digital computers when engineers used electric circuits to model mechanical systems. Suppose a \(5.0-\mathrm{kg}\) mass is connected to a spring with \(k=1.44 \mathrm{kN} / \mathrm{m} .\) This is then modeled by an \(L C\) circuit with \(L=2.5 \mathrm{H} .\) What should \(C\) be in order for the \(L C\) circuit to have the same resonant frequency as the mass-spring system?

Short Answer

Expert verified
The value of C in microfarads (µF) for the LC circuit to have the same resonant frequency as the mass-spring system is 2.0576 µF.

Step by step solution

01

Understand the Physical Correspondences and Formulas

The mass-spring system mechanical resonance frequency formula is \( f_m = \frac{1}{2\pi} \sqrt{\frac{k}{m}} \) and the electrical LC Circuit resonance frequency formula is \( f_e = \frac{1}{2\pi \sqrt{LC}} \). Here, \( f_m \) is the frequency of the mass-spring system, m is the mass, k is the spring constant, \( f_e \) is the frequency of the LC circuit, L is the inductance and C is the capacitance.
02

Substitute Known Values into the Formulas

Substitute the known values into the formulas: For the mass-spring system, \( f_m = \frac{1}{2\pi} \sqrt{\frac{1.44 \times 10^3}{5}} \). For the LC circuit, we do not know C, so the formula remains \( f_e = \frac{1}{2\pi \sqrt{2.5C}} \).
03

Equate Frequencies and Solve for Unknown

Set \( f_m \) equal to \( f_e \) and simplify: \( \frac{1}{2\pi} \sqrt{\frac{1.44 \times 10^3}{5}} = \frac{1}{2\pi \sqrt{2.5C}} \). Simplify and solve for C to find the value of capacitance that makes the LC circuit have the same resonant frequency as the mass-spring system. Solve \( C = \frac{1}{\left(2.5 \times \left(\frac{1.44 \times 10^3}{5}\right)\right)} \)

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