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Chapter 3: Problem 33

A carpenter tosses a shingle horizontally off an 8.8 -m-high roof at \(11 \mathrm{im} / \mathrm{s}\). (a) How long does it take the shingle to reach the ground? (b) How far does it move horizontally?

Short Answer

Expert verified
The time it takes for the shingle to reach the ground is roughly 1.34 seconds and the horizontal distance it covers is approximately 14.74 meters.

Step by step solution

01

Compute Time to Reach the Ground

First calculate the time it takes for the shingle to reach the ground. This can be done by using the formula \(t = \sqrt{(2h) / g}\) where \(h = 8.8m\) is the height from which the shingle is dropped and \(g = 9.81m/s^2\) is the acceleration due to gravity.
02

Calculate Horizontal Distance

Next, calculate the horizontal distance the shingle covers using the time calculated in step 1. The horizontal distance, \(d\), can be calculated using the formula \(d = vt\) where \(v = 11m/s\) is the velocity at which the shingle was thrown and \(t\) is the time taken to reach the ground.

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