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Chapter 31: Problem 2

You lay a magnifying glass (a converging lens) on a printed page. Looking toward the lens, you move it toward you, away from the page, eventually going well beyond its focal length. Explain the changes in what you see.

Short Answer

Expert verified
Initially, the magnifying glass enlarges the text on a page. As it moves away from the page and towards the observer, the magnified image gradually shrinks and becomes inverted when the lens is moved beyond its focal length.

Step by step solution

01

Understanding Converging Lenses

A converging lens (or magnifying glass) focuses parallel rays of light to a single point, producing a real, magnified, and inverted image when an object is placed at a distance greater than its focal length.
02

Visualizing The Printed Page

When the magnifying glass is close to the printed page, the image is magnified due to the light rays from the page being spread out after passing through the lens. This allows us to see the words on the page larger than they are, which is a typical function of a magnifying glass.
03

Moving The Lens

As the magnifying glass is moved away from the page and towards the observer, the light rays from the page are less spread out, and the resulting image begins to shrink and gradually gets inverted as we are moving beyond its focal length.
04

Beyond The Focal Length

Once the lens is moved beyond its focal length, the image we see becomes inverted, meaning it looks upside down. This is due to the light rays converging at a single point beyond the lens, and the observer is now viewing the image from a point where the rays have crossed each other.

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Most popular questions from this chapter

(a) Find the focal length of a concave mirror if an object placed \(50 \mathrm{cm}\) in front of the mirror has a real image \(75 \mathrm{cm}\) from the mirror. (b) Where and what type will the image be if the object is moved to a point \(20 \mathrm{cm}\) from the mirror?

For visible wavelengths, the refractive index of a thin glass lens is \(n=n_{0}-b \lambda,\) where \(n_{0}=1.546\) and \(b=4.47 \times 10^{-5} \mathrm{nm}^{-1} .\) If its focal length is \(30 \mathrm{cm}\) at \(550 \mathrm{nm}\), how much does the focal length vary over a wavelength spread of 10 nm centered on 550 nm?

How can you see a virtual image, when it's not "really there"?

A candle and a screen are \(70 \mathrm{cm}\) apart. Find two points between candle and screen where you could put a convex lens with 17 -cm focal length to give a sharp image of the candle on the screen.

You're given two lenses with different diameters. Knowing nothing else, you can conclude that a. the larger lens is faster. b. the smaller lens has the shorter focal length. c. the smaller lens suffers less spherical aberration. d. none of the above
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