Use shell notation to characterize rubidium's outermost electron.

Short Answer

Expert verified
The shell notation for Rubidium's outermost electron is in the 5s orbital.

Step by step solution

01

Identify the Atomic Number

Rubidium is represented by the symbol Rb in the Periodic table, and it has an atomic number of 37. The atomic number represents the number of protons in the nucleus of the atom and also tells us the number of electrons in a neutral atom.
02

Understand the energy levels and electron shells

Electrons in an atom are located in energy levels called shells, and these have sub-levels or sub-shells. The energy levels are given by the principal quantum numbers \(n = 1, 2, 3, ... \) and the sub-levels are designated as \(s, p, d, f\). Each energy level can accommodate a certain number of electrons: 2 for a \(s\) sub-shell, 6 for a \(p\) sub-shell, 10 for a \(d\) sub-shell, and 14 for an \(f\) sub-shell. We follow the 'Aufbau principle' which states that electrons fill up the energy levels from the lowest to the highest.
03

Determine the electron configuration

To find the electron configuration of Rubidium, we fill up the electron shells according to the Aufbau principle until we have 37 electrons. The electron configuration for Rubidium is: \(1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^6 5s^1\).
04

Characterize the Outermost Electron

The last part of the electron configuration (\(5s^1\)) is for the outermost electron of rubidium. So the shell notation for the outermost electron of Rubidium is in the 5s orbital.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Number
Understanding the atomic number is fundamental in chemistry. It's like an atom's personal ID number, unique to each element, defined by the number of protons in an atom's nucleus. In a neutral atom, the atomic number also tells us how many electrons orbit around the nucleus because an atom in its neutral state has an equal number of protons and electrons.

For instance, rubidium (Rb) has an atomic number of 37, meaning it has 37 protons and, in a neutral state, 37 electrons. This atomic number not only identifies the element but also helps us determine its position in the periodic table and its chemical properties, including its electron configuration. Knowing the atomic number is the start point for many chemical calculations and understanding electron configurations.
Energy Levels and Electron Shells
Electrons reside in specific regions around an atom's nucleus known as energy levels or electron shells. These levels are like the floors in a hotel, with rooms (sub-shells) that can house electrons. The energy levels are organized by principal quantum numbers (\(n = 1, 2, 3, ...\)), which increase with distance from the nucleus. Moreover, each level has sub-levels designated as s, p, d, and f.

Each sub-shell has a maximum capacity of electrons it can hold: 2 for an s sub-shell, 6 for a p sub-shell, 10 for a d sub-shell, and 14 for an f sub-shell. These capacities are essential for building up an atom's electron configuration, as we place electrons in these sub-shells according to certain rules, such as the Aufbau principle. Understanding the arrangement of these shells and sub-shells is instrumental in figuring out how atoms will bond and interact with each other.
Aufbau Principle
The Aufbau principle is a brilliant strategy that electrons use to organize themselves within an atom. It's like when you're packing a suitcase – you start with the essentials and then add in extra items where you find space. Similarly, in atomic terms, the Aufbau principle dictates that electrons fill lower-energy orbitals first before moving to higher-energy ones. This principle allows us to predict the electron configurations of atoms.

The rule gets its name from the German 'Aufbau,' meaning 'building up.' Following this principle, we fill the s sub-shell before p, then d, and finally f. This strategy guides us in writing the electron configuration of elements, as we've done for rubidium. As a result, we can determine the outermost electron and its probable chemical behavior, significantly aiding in the comprehension of atomic interactions and bonding patterns.

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Most popular questions from this chapter

Both the Bohr and Schrödinger theories predict the same groundstate energy for hydrogen. Do they agree about the angular momentum in the ground state? Explain.

Adapt part (b) of Example 36.1 to find the probability that an electron in the hydrogen ground state will be found beyond two Bohr radii.

A selection rule for the infinite square well allows only those transitions in which \(n\) changes by an odd number. Suppose an infinite square well of width \(0.200 \mathrm{nm}\) contains an electron in the \(n=4\) state. (a) Draw an energy-level diagram showing all allowed transitions that could occur as this electron drops toward the ground state, including transitions from lower levels that could be reached from \(n=4 .\) (b) Find all the possible photon energies emitted in these transitions.

Helium and lithium exhibit very different chemical behavior, yet they differ by only one unit of nuclear charge. Explain.

With sufficient energy, it's possible to eject an electron from an inner atomic orbital. A higher-energy electron will then drop into the unoccupied state, emitting a photon with energy equal to the difference between the two levels. For inner-shell electrons, photon energies are in the keV range, putting them in the X-ray region of the spectrum. These characteristic X rays are labeled with the letter indicating the shell to which the electron drops, followed by a Greek letter indicating the higher level from which it drops; thus \(K \alpha\) designates a transition from the \(L\) shell to the \(K\) shell. Characteristic X rays provide scientists and physicians with an important diagnostic tool. Environmental scientists bombard pollution samples with high- energy electrons, knocking out inner-shell electrons and thus producing X-ray spectra that help identify contaminants (Fig. \(36.20 a\) ). Geologists do the same with rocks. Medical radiologists reverse the process, exploiting the fact that X rays cause inner-shell transitions as well as complete ejection of inner-shell electrons. In particular, radiologists use the element barium in this way to produce high-contrast X-ray images of the intestinal tract \((\text { Fig. } 36.20 b)\)(GRAPH CANNOT COPY) (a) An \(\mathrm{X}\) -ray spectrum from air pollutants trapped on a filter. The labeled peaks show the presence of lead (Pb) and arsenic (As), as evidenced by \(K \alpha, K \beta, L \alpha,\) and \(L \beta\) characteristic X rays. (b) \(\mathrm{X}\) -ray of an intestinal tract, made by coating the intestinal wall with X-ray-opaque barium Elements \(A\) and \(B\) have atomic numbers \(Z_{A}\) and \(Z_{B}=2 Z_{A} .\) How do you expect element \(B^{\prime}\) s \(K \alpha\) X-ray energy to compare with that of element \(A\) ? a. \(B^{\prime}\) s \(K \alpha\) energy should be about one-fourth that of \(A\) b. \(B\) 's \(K \alpha\) energy should be about half that of \(A\) c. \(B^{\prime}\) s \(K \alpha\) energy should be about twice that of \(A\) d. \(B^{\prime}\) s \(K \alpha\) energy should be about four times that of \(A\)

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