A hydrogen atom is in an \(l=2\) state. What are the possible angles its orbital angular momentum vector can make with a given axis?

Short Answer

Expert verified
The orbital angular momentum vector can make angles of 0º, 60º, 90º, 120º, and 180º with the given axis.

Step by step solution

01

Calculate the Magnetic Quantum Number Ranges

Given that \(l\) is 2, the magnetic quantum number can range from \(-l\) to \(+l\). Consequently, \(m\) ranges from -2 to +2 with these possible values: -2, -1, 0, 1, 2.
02

Define the Possible Angles

Each of the \(m\) values corresponds to a particular orientation of the orbital, and thus a particular angle \(\theta\), the angle that the orbital angular momentum vector makes with the z-axis. These angles \(\theta\) can be found using the relation \(\cos(\theta) = m/l\). Compute these values by using the obtained \(m\) values from Step 1.
03

Determine the Angular Measurements

The angles associated with the \(m\) values, in ascending order, are \(acos(-2/2) = 180^\circ~, acos(-1/2) = 120^\circ~, acos(0/2) = 90^\circ~, acos(1/2) = 60^\circ~, acos(2/2) = 0^\circ\).

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