Repeat Exercise 25 for the case where you know only that the principal quantum number is \(3 ;\) that is, \(l\) might have any of its possible values.

Short Answer

Expert verified
The possible values for the orbital quantum number 'l' are 0, 1, and 2.

Step by step solution

01

Understand quantum numbers

In quantum mechanics, quantum numbers describe the specific state an electron in an atom can be in. The principal quantum number \(n\) describes the energy level of the atom where the electron resides. The orbital quantum number \(l\), represents the shape of the electron's orbit.
02

Determine possible values for 'l'

The value of the orbital quantum number \(l\) can be any integer within the range from 0 to the value of the principal quantum number \(n\) minus 1. Since we have \(n=3\), the possible values for \(l\) would be 0, 1, and 2.
03

Summarize the solution

Given a principal quantum number \(n=3\), we find that the orbital quantum number (\(l\)) could have any value between 0 and 2.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Write the full electronic structure of bromine.

What distinguishes a Bose-Einstein condensate from ordinary matter?

Use shell notation to characterize rubidium's outermost electron.

With sufficient energy, it's possible to eject an electron from an inner atomic orbital. A higher-energy electron will then drop into the unoccupied state, emitting a photon with energy equal to the difference between the two levels. For inner-shell electrons, photon energies are in the keV range, putting them in the X-ray region of the spectrum. These characteristic X rays are labeled with the letter indicating the shell to which the electron drops, followed by a Greek letter indicating the higher level from which it drops; thus \(K \alpha\) designates a transition from the \(L\) shell to the \(K\) shell. Characteristic X rays provide scientists and physicians with an important diagnostic tool. Environmental scientists bombard pollution samples with high- energy electrons, knocking out inner-shell electrons and thus producing X-ray spectra that help identify contaminants (Fig. \(36.20 a\) ). Geologists do the same with rocks. Medical radiologists reverse the process, exploiting the fact that X rays cause inner-shell transitions as well as complete ejection of inner-shell electrons. In particular, radiologists use the element barium in this way to produce high-contrast X-ray images of the intestinal tract \((\text { Fig. } 36.20 b)\)(GRAPH CANNOT COPY) (a) An \(\mathrm{X}\) -ray spectrum from air pollutants trapped on a filter. The labeled peaks show the presence of lead (Pb) and arsenic (As), as evidenced by \(K \alpha, K \beta, L \alpha,\) and \(L \beta\) characteristic X rays. (b) \(\mathrm{X}\) -ray of an intestinal tract, made by coating the intestinal wall with X-ray-opaque barium Molybdenum's X-ray spectrum has its \(K \alpha\) peak at 17.4 keV. The corresponding X-ray wavelength is closest to a. \(1 \mathrm{pm}\) b. \(100 \mathrm{pm}\) c. \(1 \mathrm{nm}\) d. \(100 \mathrm{nm}\)

Find the maximum possible magnitude for the orbital angular momentum of an electron in the \(n=7\) state of hydrogen.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free