Chapter 37: Problem 47
Integrating Equation 37.5 over all energies gives the total number of states per unit volume in a metal. Therefore, integrating from \(E=0\) to \(E=E_{\mathrm{F}}\) - that is, over the occupied states only-gives the number of conduction electrons per unit volume. Carry out this integration to show that the electron number density is given by $$n=\left(\frac{2^{9 / 2} \pi m^{3 / 2}}{3 h^{2}}\right) E_{\mathrm{F}}^{3 / 2}$$
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