Copper-64 can decay by any of the three beta-decay processes. Write the equation for each decay.

Short Answer

Expert verified
The decay equations are: Beta-minus decay: \[ \, _{29}^{64} \text{Cu} \rightarrow \, _{30}^{64} \text{Zn} + e^- + \bar{v}_e \]. Beta-plus decay: \[ \, _{29}^{64} \text{Cu} \rightarrow \, _{28}^{64} \text{Ni} + e^+ + v_e \]. Electron capture: \[ \, _{29}^{64} \text{Cu} + e^- \rightarrow \, _{28}^{64} \text{Ni} + v_e \].

Step by step solution

01

Write the Equation for Beta-minus Decay

In the beta minus decay, Cu-64 changes a neutron into a proton and emits an electron (beta particle) and an antineutrino. We write this equation as: \[ \, _{29}^{64} \text{Cu} \rightarrow \, _{30}^{64} \text{Zn} + e^- + \bar{v}_e \]. Where \(_{30}^{64}\)Zn is the zinc atom obtained after decay, \(e^-\) is the beta particle (electron), and \(\bar{v}_e\) is an electron antineutrino.
02

Write the Equation for Beta-plus Decay

In the beta plus decay, Cu-64 changes a proton into a neutron, and emits a positron (the anti-particle of the electron) and a neutrino. We write this equation as: \[ \, _{29}^{64} \text{Cu} \rightarrow \, _{28}^{64} \text{Ni} + e^+ + v_e \]. Where \(_{28}^{64}\)Ni is the nickel atom after decay, \(e^+\) is the positron, and \(v_e\) is the electron neutrino.
03

Write the Equation for Electron Capture

In electron capture, Cu-64 absorbs an inner shell electron which combines with a proton to make a neutron, emitting a neutrino. We write this equation as: \[ \, _{29}^{64} \text{Cu} + e^- \rightarrow \, _{28}^{64} \text{Ni} + v_e \]. Where \(e^-\) is the inner shell electron, \(_{28}^{64}\)Ni is the nickel atom after electron capture, and \(v_e\) is the neutrino.

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