You measure the activity of a radioactive sample at \(2.4 \mathrm{MBq}\). Thirty minutes later, the activity level is 1.9 MBq. Find the material's half-life.

Short Answer

Expert verified
The half-life of the radioactive sample is calculated using the derived decay constant \(k\), by substituting into the formula for half-life \(T_{1/2}\) as \(T_{1/2} = \frac{ln(2)}{k}\).

Step by step solution

01

Identify given quantities

Identify the given quantities in the problem: the initial activity level \(N_0 = 2.4 MBq\), the activity level after some time \(N = 1.9 MBq\), and the time \(t = 0.5\) hours
02

Set up the decay equation

Use the given quantities to set up the decay equation \(N = N_0e^{kt}\). In this case, \(1.9 = 2.4e^{0.5k}\).
03

Solve for the decay constant k

Solve the equation for the decay constant \(k\). This involves isolating \(k\) on one side of the equation, which can be done in several steps. First, divide both sides of the equation by 2.4 to get \(\frac{1.9}{2.4} = e^{0.5k}\). Then, take the natural logarithm of both sides to get \(ln\left(\frac{1.9}{2.4}\right) = 0.5k\). Divide again by 0.5 to finally solve for \(k\).
04

Calculate half-life

Use the decay constant \(k\) to calculate the half-life of the radioactive material. The formula for the half-life \(T_{1/2}\) is derived from the decay equation, and is given by \(T_{1/2} = \frac{ln(2)}{k}\).

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