A small plane accelerates down the runway at \(7.2 \mathrm{m} / \mathrm{s}^{2} .\) If its propeller provides an \(11-\mathrm{kN}\) force, what's the plane's mass?

Short Answer

Expert verified
The mass of the plane is approximately 1527.8 kg

Step by step solution

01

Understand Newton’s Second Law of Motion

The Newton’s Second Law of motion states that the force applied to an object is equal to the mass of the object multiplied by the acceleration of the object. In other words, it can be defined as \( F = m*a \) where F is the force, m is the mass, and a is the acceleration.
02

Set up the equation

Set up the equation based on Newton’s Second Law formula. Given that the force (F) is 11 kN (which is 11000 N) and acceleration (a) is 7.2 m/s^2, the equation becomes 11000 = m*7.2.
03

Solve for the mass

Use the equation derived in the previous step to solve for the mass (m) by dividing both sides by the acceleration. That is, \( m = \frac{11000}{7.2} \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free