A block is launched with speed \(v_{0}\) up a slope making an angle \(\theta\) with the horizontal; the coefficient of kinetic friction is \(\mu_{\mathrm{k}}\) (a) Find an expression for the distance \(d\) the block travels along the slope. (b) Use calculus to determine the angle that minimizes \(d\).

Short Answer

Expert verified
The expression for the distance \(d\) the block travels up the slope before coming to rest is given by\( d = \frac{v_0^2}{2 g [\sin(\theta) + \mu_k \cos(\theta)]} \)The angle \(\theta\) that minimizes this distance d is given by \( \tan(\theta) = \mu_{k} \)

Step by step solution

01

Analyse the involved Forces

There are two primary forces acting on the block as it travels up the slope: the force of gravity and the force of friction. Given the block travels up the incline, the frictional force \( f = mu_k m g cos(\theta) \) and the component of gravitational force acting along the slope \( F_g = m g sin(\theta) \).
02

Find Work Done by Friction and Gravity

The total work done by all forces - gravity and friction - will be equal to the initial kinetic energy since all of the block's kinetic energy will be used to do work against these forces. Using the work-energy theorem, the work done \(W = \frac{1}{2} m v_0^2\). The work done by friction and gravity are \( W_{\text{friction}} = f d = \mu_k m g cos(\theta) d \) and \( W_{\text{gravity}} = F_g d = m g sin(\theta) d \) respectively.
03

Derive Expression for Distance

Setting the total initial energy equal to the total work done gives us:\( \frac{1}{2} m v_0^2 = [m g sin(\theta) + \mu_k m g cos(\theta) ] d\)\[d = \frac{v_0^2}{2 g [sin(\theta) + \mu_k cos(\theta) ]}\]This is the expression for the distance the block travels up the slope before coming to rest.
04

Find angle that minimizes d

To find the angle \( \theta \) that minimizes the distance d, we first note that \( d = \frac{v^{2}_{0}}{2 g [\sin(\theta) + \mu_{k} \cos(\theta)]} \). To find minimum, we take its derivative with respect to \( \theta \) and set the derivative equal to zero.\( \frac{d}{d \theta} (\frac{1}{sin(\theta) + \mu_{k} cos(\theta)}) = 0 \)Solving this equation gives us \( tan(\theta) = \mu_{k} \), which provides us the minimum angle.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Friction
Kinetic friction is a force that opposes the motion of two surfaces sliding past each other. It's always there when we see objects moving across surfaces, like a block sliding down a ramp or across a table. The strength of this frictional force depends on two things: the nature of the surfaces in contact (which is captured by the coefficient of kinetic friction, \(\mu_k\)) and how much the surfaces are pushed together (which is determined by the normal force).

In our problem, the friction between the block and the slope is \(\mu_k m g \cos(\theta)\), where \(m\) is the mass of the block, \(g\) is the acceleration due to gravity, and \(\theta\) is the angle of the incline. The \(\cos(\theta)\) term adjusts the weight of the block to reflect the portion acting perpendicular to the incline. This kinetic friction is what eventually stops the block from moving up the slope, as it works against the motion.
Work-Energy Theorem
The work-energy theorem is a fundamental principle in physics that describes the relationship between the work done on an object and its kinetic energy. We define work as the product of force and displacement in the direction of the force. According to the theorem, if an object's kinetic energy changes, work has been done on the object.

This theorem is brilliantly showcased in the question at hand. The block starts with some kinetic energy due to its initial velocity, \(v_0\), and this energy is then dissipated by the work done against gravity and the kinetic frictional force as it goes up the incline. Mathematically, the initial kinetic energy, \(\frac{1}{2} m v_0^2\), is equal to the sum of the work done by friction and gravity. Thus, by applying the work-energy theorem, we can find how far the block will travel up the slope. It is fascinating how this fundamental principle provides a straightforward way to analyze systems involving multiple forces and energy conversions.
Inclined Plane
An inclined plane is a flat surface that is tilted at an angle to the horizontal. This simple machine helps us lift heavy objects by spreading the work over a longer distance. Similarly, when a block slides up an inclined plane, the component of the gravitational force making it slide back down is less compared to if it were just falling straight down.

In our problem, the angle of the incline, \(\theta\), directly affects the distance the block will travel before coming to a stop. A steeper slope (larger \(\theta\)) means a stronger gravitational pull down the slope. When we introduce the concept of finding an angle that minimizes the distance \(d\) traveled by the block, we delve into optimizing the situation, demonstrating how angles can be adjusted to control the behavior of objects on an incline. This adds a layer of complexity to problems involving inclined planes, where geometry and physics interplay to predict and control motion.

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